Answer:
1/3 of black F2 progeny will be homozygous.
Explanation:
Here, BB = black coat color = true breeding dominant black strain
bb = white coat color = true breeding recessive white strain
When true breeding black and white guinea pigs are mated to give F1 progeny:
BB X bb = Bb ( all black guinea pigs )
When two of the F1 guinea pigs are mated to give F2 progeny:
Bb X Bb = BB, Bb, Bb, bb
F2 progeny has 3/4 progeny as black (BB and Bb) . Out of them 1/3 are homozygous and 2/3 are heterozygous.
Hence, 1/3 of black F2 progeny will be homozygous.
The correct answer is option A, a popular culture magazine
Reason -
A cultural magazine covers the stories from the field of art and culture and has no relations with the medical field. The content of a cultural magazine primarily includes latest trends in the field of art and culture and their impacts on the society.
Here some may also refer to the popular “CULTURE” magazine of America which talks about cannabis community. It was published with an intention of entertaining 5,00,000+ cannabis patient thought the content of magazine which includes news, legal advice, event , music, travel column, strain and edible reviews, CD/DVD/film/book reviews, recipes, photo galleries and an extensive events calendar
Answer:
Unisexual and bisexual organisms are differentiated based on the reproductive systems they posses. Unisexual organisms have separate sexes male or female. Male and female reproductive systems are present in different individuals hence unisexual organisms produce male or female gametes but never both. Bisexual organisms have both male and female reproductive systems within the same individual. Hence, they are capable of producing both types of gametes. Some flowers are unisexual, and they possess only pistils or stamens. Some flowers are bisexual, and they possess both stamens and pistils together. This is the difference between unisexual and bisexual organisms.
Question is cute off pls repost or tell me the question
Answer:
The correct answer is option a, that is, the thrM and thrN would be transcribed at high levels in comparison to non-mutant.
Explanation:
Based on the given information, in the existence of thorain the expression of thrM and thrN will be prevented as thorain functions as a negative regulator. In case, if the gene, which codes for thorain, that is, thrL gets mutated, the coding for the functional thorain would get prevented.
With the encoding of the non-functional thrL protein, there would be an enhancement in the expression of thrN and thrM genes and it will get transcribed at higher levels in comparison to the non-mutant or the wild-type.
