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Masja [62]
3 years ago
8

Find the balance after 40 years of a $15,000 investment earning 9% interest compounded continuously.

Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Answer:

B

Step-by-step explanation:

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2k to the power of 6 over 8k to the power of 2
Readme [11.4K]

Answer:

1000000000000

Step-by-step explanation:

2000^6/8000^2=1000000000000

7 0
3 years ago
Read 2 more answers
Can someone please help me with 7-
Helga [31]

Answer:

The answer is the second one , 0=5 , no solutions .

Step-by-step explanation:

Good luck

5 0
3 years ago
A candidate for a US Representative seat from Indiana hires a polling firm to gauge her percentage of support among voters in he
UkoKoshka [18]

Answer:

a) The minimum sample size is 601.

b) The minimum sample size is 2401.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

For this problem, we have that:

We dont know the true proportion, so we use \pi = 0.5, which is when we are are going to need the largest sample size.

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

a. If a 95% confidence interval with a margin of error of no more than 0.04 is desired, give a close estimate of the minimum sample size that will guarantee that the desired margin of error is achieved. (Remember to round up any result, if necessary.)

This is n for which M = 0.04. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.04\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.04}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.04})^2

n = 600.25

Rounding up

The minimum sample size is 601.

b. If a 95% confidence interval with a margin of error of no more than 0.02 is desired, give a close estimate of the minimum sample size necessary to achieve the desired margin of error.

Now we want n for which M = 0.02. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.02 = 1.96\sqrt{\frac{0.5*0.5}{n}}

0.02\sqrt{n} = 1.96*0.5

\sqrt{n} = \frac{1.96*0.5}{0.02}

(\sqrt{n})^2 = (\frac{1.96*0.5}{0.02})^2

n = 2401

The minimum sample size is 2401.

4 0
3 years ago
What is the following product?
Aneli [31]
Your correct it’s the first one
4 0
2 years ago
The sum of two consecutive integers is 85. What are those two<br> integers?
chubhunter [2.5K]

Answer:

41 and 42

Step-by-step explanation:

Let the integers be x and x + 1

=> x + x + 1 = 85

=> 2x + 1 = 85

=> 2x = 84

=> x = 84/2

=> x = 41

Integers are :

41 and 42

7 0
2 years ago
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