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3 years ago

Can you please help me with this question.

Mathematics

1 answer:

blondinia [14]3 years ago

4 0

Answer:

Step-by-step explanation:

this my answer is perfect yap

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iris has 120 songs on her playlist each week she downloads 4 new songs. write an expression to show the total number of songs on

Leni [432]

Answer:

4 W = n of songs on her playlist

$n \leqslant 120$

6 0

3 years ago

Find the 18th term of the sequence<br> a19 = -7, d= - 17

sineoko [7]

Answer:

Step-by-step explanation:

aₙ₊₁ = aₙ + d

a₁₉ = a₁₈ + d

- 7 = a₁₈ + (-17)

a₁₈ = - 7 +17

a₁₈ = 10

7 0

3 years ago

Two students, X and Y, forgot to put their names on their exam papers. The professor knows that these two students do well on th

Luda [366]

Answer:

The probability that the good exam belongs to student <em>X</em> is 0.8571.

Step-by-step explanation:

It is provided that the probability that <em>X</em> did well in the exam is, P (X) = 0.90 and the probability that <em>X</em> did well in the exam is, P (Y) = 0.40,

Compute the probability that exactly one student does well in the exam as follows:

$P(Either\ X\ or\ Y\ did\ well)=P(X\cap Y^{c})+P(X^{c}\cap Y)\\=P(X)P(Y^{c})+P(X^{c})P(Y)\\=P(X)[1-P(Y)]+[1-P(X)]P(Y)\\=(0.80\times0.60)+(0.20\times0.40)\\=0.56$

Then the probability that <em>X</em> is the one who did well in the exam is:

$P(X\ did\ well\ in\ the\ exam)=\frac{P(X\cap Y^{c})}{P(X\cap Y^{c})+P(X^{c}\cap Y)}\\ =\frac{P(X)[1-P(Y)]}{P(X\cap Y^{c})+P(X^{c}\cap Y)} \\=\frac{0.80\times0.60}{0.56}\\=0.857143\\\approx0.8571$

Thus, the probability that the good exam belongs to student <em>X</em> is 0.8571.

8 0

3 years ago

Two functions, P and Q, are described as follows: Function P y = 5x + 3 Function Q The rate of change is 2 and the y-intercept i

Svetach [21]

Function P . . . . . y = 5x + 3

Function Q . . . . . y = 2x + 4

Function P rate of change = 5
Function Q rate of change = 2

The first one is => 3 <= more than second one.

7 0

4 years ago

Read 2 more answers

What is the length of JK¯¯¯¯¯, to the nearest tenth of a millimeter? 4.5 mm 5.6 mm 8.3 mm 19.9 mm A horizontally-aligned scalene

Leokris [45]

Answer:

5 = side a

3 = side c

angle B = 62 degrees

JK is side b

Use the Law of Cosines to find the length of side b.

b^2 = a^2 + c^2 − 2ac cos(B)

b^2 = (5^2 + 3^2) − ( 2 x 5 x 3) cos(62°)

b^2 = (25 + 9) − 30 x 0.469

b^2 = 34 - 30 x 0.469

b^2 = 34 - 14.084

b^2 = 19.916

b = √19.916

b = 4.463

Rounded to the nearest tenth is 4.5 mm.

Hope this helps!

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can you please help me with this question. ​

Can you please help me with this question.