A.) The radius of vessel has the greatest affect on blood flow.(brainliest plz)
Answer:
Scientists are perhaps some of the smart few that make up the human population and are never short on knowledge. They research and discover and conduct tests to gain more knowledge, but the answer to your question is stars are huge celestial bodies made mostly of hydrogen and helium that produce light and heat from the churning nuclear forges inside their cores, and scientist know this because of their research.
Explanation:
<span>Cocaine Preparations
-Coca leaves --> Coca Paste (60% pure): Not water soluble, so you can't inject it into the bloodstream -- you need an additional chemical step to turn the paste into crystal powder that can be injected or snorted
-Coca --> Cocaine Hydrochloride (99% pure): Doesn't hold up very well to heat, so you can't smoke cocaine hydrochloride
-Cocaine Hydrochloride (99% pure) --> Free-Base Cocaine or Crack Cocaine:
-Reconvert cocaine hydrochloride back to base state by removing hydrochloride from cocaine (that's why it's called free-base cocaine)
-Crack cocaine is a crystallized form, mixture of cocaine and baking soda
-75% pure
-Can be used at lower doses and is much cheaper than cocaine
-Can be smoked</span>
Answer:
1/8
Explanation:
Given that the trihybrid parents have AaBbCc genotype for fruit color. The trait is a quantitative trait i.e. each dominant allele will have an additive effect on it. In this case, AaBbCc and AABBCC will not produce same fruit color because AaBbCc has only three loci contributing to the color while in AABBCC all the six loci are contributing to the color. For an offspring to be exactly similar to the AaBbCc parents it should have the same genotype of AaBbCc.
The probability of Aa to come from a cross between Aa and Aa is 2/4 or 1/2
The probability of Bb to come from a cross between Bb and Bb is 2/4 or 1/2
The probability of Cc to come from a cross between Cc and Cc is 2/4 or 1/2
So the collective probability of AaBbCc offspring from a cross between AaBbCc and AaBbCc parents would be=
1/2 * 1/2 * 1/2 = 1/8
Hence, assuming no effects of the environment, 1/8 of the offspring will have the same fruit color phenotype as the trihybrid parent.
