Answer:
-13
Step-by-step explanation:
3x^3 - 2y^-6x^2y^2+xy
x=2/3 and y=1/2
Solve :
3x^3 - 2y^-6x^2y^2+xy
Put value of x and y in this equation
= 3(2/3)^3 - 2(1/2)^-6(2/3)^2(1/2)^2+(2/3)(1/2)
= -13
The possible values of x are 5 and -1/12
<h3>Complete question</h3>
Given that 2x − 1∶ x − 4 = 16x + 1 ∶ 2x − 1 find the possible values of x
<h3>How to determine the possible values of x?</h3>
The ratio is given as:
2x − 1∶ x − 4 = 16x + 1 ∶ 2x − 1
Express as fraction

Cross multiply
4x^2 -4x + 1 = 16x^2 + x -64x - 4
Collect like terms
-16x^2 + 4x^2 + 64x - x - 4x + 1 + 4 = 0
Evaluate the like terms
-12x^2 + 59x + 5 = 0
Divide through by -1
12x^2 - 59x - 5 = 0
Expand
12x^2 + x - 60x - 5 = 0
Factorize
x(12x + 1) - 5(12x + 1) = 0
Factor out 12x + 1
(x - 5)(12x + 1) = 0
Expand
x - 5 = 0 or 12x + 1 = 0
Solve for x
x = 5 or x = -1/12
Hence, the possible values of x are 5 and -1/12
Read more about ratios at:
brainly.com/question/2328454
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No two numbers will work for this.
Answer:
54m^2
Step-by-step explanation:
Area for a triangle = 1/2(12*9)
12 x 9 = 108
108/2 = 54