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AlladinOne [14]
3 years ago
6

Solve the equation for x. 22x = 198 X=

Mathematics
1 answer:
guapka [62]3 years ago
6 0

Answer:

9

Step-by-step explanation:

22x = 198

divide both sides by 22

22x/22 = 198/22

x = 9

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Dale is riding his bicycle. He rides at a speed of 9 kilometers per hour for 14.4
lesya [120]

Answer:

He rides for 1.6 hours.

Step-by-step explanation:

14.4 divided by 9 is 1.6

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Please answer this question​
alisha [4.7K]

Answer:

36.

Step-by-step explanation:

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sec^2 (2π/9) = 1 / cos^2 (2π/9) = 1.70409

sec^2 (4π/9) = 1 / cos^2 (4π/9) = 33.1634

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3 years ago
Four friends are standing in line to buy tickets. Carlos is not first in line. Paige is ahead of Kate. Lisa is last in line. 
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Well Carlos obviously isn't first, and the question states that Lisa is last.
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Lise
4 0
3 years ago
PLEASE HELP RIGHT AWAY, NEED URGENT HELP, WILL GIVE BRAINLIEST!
elena-s [515]

Answer:

<h2>g is a GEOMETRIC SEQUENCE</h2><h2>Explicit formula g(n) = 900(\frac{1}{3})^{n-1}</h2>

Step-by-step explanation:

If wanahton purified a portion of water with 900 grams of contaminants and each hour, a third of the contaminants was filtered out then the amount of grams filtered out first hour will be 1/3 of 900grams = 300grams.

The amount filtered out in the second hour will be 1/3 of 300grams = 100grams.

Given the initial amount of contaminant = 900g

Contaminant after 1st hour = 300g

contaminant after 2nd hour = 100g and so on

It is seen that the amount of contaminant keep reducing by one third each hour. The sequence formed will be 900, 300, 100... which is a GEOMETRIC SEQUENCE because they are reducing by the same factor each term which is 1/3.

Given the geometric sequence 900, 300, 100...the nth term of the sequence is expressed as shown;

g(n) = ar^{n-1}

r is the common ratio = \frac{300}{900}= \frac{100}{300} =  \frac{1}{3}

n is the umber of terms

a is the first term which serves as the initial value of the contaminant= 900

Substituting the values given to get the explicit formula for the sequence we have;

g(n) = 900(\frac{1}{3})^{n-1}

The amount of contaminants (in grams) that remained by the beginning of the nth hour is 900(\frac{1}{3})^{n-1}

5 0
2 years ago
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