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Greeley [361]
3 years ago
12

Find the solution to the system of equations represented by this matrix equation using an inverse matrix.

Mathematics
1 answer:
8090 [49]3 years ago
4 0

Answer:

  D) \left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right]

Step-by-step explanation:

For matrix \left[\begin{array}{cc}a&b\\c&d\end{array}\right]

the inverse matrix is the transpose of the cofactor matrix, divided by the determinant: \dfrac{1}{ad-bc}\left[\begin{array}{cc}d&-b\\-c&a\end{array}\right]

Your inverse matrix is: \dfrac{1}{2(-3)-(1)(2)}\left[\begin{array}{cc}-3&-1\\-2&2\end{array}\right]

so the solution is ...

\left[\begin{array}{c}x\\y\end{array}\right]=\left[\begin{array}{cc}\frac{3}{8}&\frac{1}{8}\\\frac{1}{4}&-\frac{1}{4}\end{array}\right] \cdot\left[\begin{array}{c}2\\4\end{array}\right] =\left[\begin{array}{c}\frac{5}{4}\\-\frac{1}{2}\end{array}\right] \qquad\text{matches selection D}

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Sladkaya [172]

Answer:

The value is c = 21.1445.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the z-score of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

The weight distribution of parcels sent in a certain manner is normal with mean value 12lb and standard deviation 3.5 lb.

This means that \mu = 12, \sigma = 3.5

What value of c is such that 99% of all parcels are at least 1 lb under the surcharge weight?

This 1 added to the value of X for the 99th percentile, which is X when Z has a p-value of 0.99, so X when Z = 2.327.

Z = \frac{X - \mu}{\sigma}

2.327 = \frac{X - 12}{3.5}

X - 12 = 2.327*3.5

X = 20.1445

1 + 20.1445 = 21.1445

The value is c = 21.1445.

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3 years ago
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3 years ago
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