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Fantom [35]
3 years ago
5

A-bcosc/c-bcosa=sinc/sina​

Mathematics
1 answer:
Westkost [7]3 years ago
6 0

=ac-b(cosc-ccosa)

=sinc/sina

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Given: ⅓ (18x + 27) = 81 Prove: x = 12
sasho [114]

Answer:

Firstly, rewrite the equation:

⅓ (18 + 27) = 81

Substitute x for the given number of it's supposed equivalent.

In this case x = 12.

⅓ (18(12) + 27) = 81

Solve using PEMDAS and simplify what is in the parenthesis first. Then, multiply.

(18 x 12) + 27 = 243

Now, solving using PEMDAS, multiply the total of what you got that was originally in the parenthesis by ⅓ .

⅓ (243) = 81

When you multiple these number they are equivalent to 81.

81 = 81

Since the equation given, when substituted x for 12, is equivalent to 81, this proves that substituting x for 12 makes this equation true.

4 0
3 years ago
If g(x)=7x²−4x−3 and h(x)=5x²−12x, find (h∘g)(1)<br><br><br>FIRST BEST ANSWER BRAINLIEST
AURORKA [14]

Answer: See below

Step-by-step explanation:

h\:\circ \:g=h\left(g\left(x\right)\right)

=5\left(7x^2-4x-3\right)^2-12\left(7x^2-4x-3\right)

=5\left(7x^2-4x-3\right)\left(7x^2-4x-3\right)-12\left(7x^2-4x-3\right)

=245x^4-280x^3-130x^2+120x+45-84x^2+48x+36

Simplify:

=245x^4-280x^3-214x^2+168x+81

6 0
3 years ago
You are dealt one card from a standard 52 card deck find the probability of being dealt a king and a jack
OLga [1]

Answer:

zjvmNxn

Step-by-step explanation:

sxcxz

7 0
3 years ago
Simplify the rational expressions. State any excluded values. X^2-4/2-x
tatiyna

Answer:

-x-2;  x\neq2

Step-by-step explanation:

\frac{x^2-4}{2-x}-->

\frac{(x-2)(x+2)}{(2-x)} -->

-(x+2); x CAN'T equal 2, because the denominator of the original fraction would be 0, which would make the term undefined.

4 0
3 years ago
If a single card is drawn from a standard 52-card deck, what is the probability that it is an ace or a spade?
klasskru [66]

A 52-card deck is made up of an equal number of diamonds, hearts, spades, and clubs. Because there are 4 suits, there is a 1/4 chance to draw one of them, in our case, spades.

There are 4 aces in a 52-card deck, so the chance of drawing one is 4/52, or 1/13.

The question asks for the probability of drawing an ace or a spade. Because it uses the word "or," we add the probabilities together. This is because there is a chance of drawing either of the cards; it doesn't have to meet both requirements to satisfy the statement.

However, if the question were to say "and," we would multiply the two probabilities.

Let's add 1/4 and 1/13. First, we can find a common denominator. We can use 52 because both fractions can multiply into it (since the ratio came from a deck of 52 cards as well).

\frac{1}{4} -- > \frac{13}{52}

\frac{1}{13} -- > \frac{4}{52}

Now we can add them together.

\frac{13}{52} + \frac{4}{52} = \frac{13+4}{52} = \frac{17}{52}

This cannot be simplified further, so the probability is 17 in 52, or 33%.

hope this helps!

7 0
1 year ago
Read 2 more answers
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