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mel-nik [20]
3 years ago
8

Please Help! Please write a sentence or more about the difference between​ each plot

Mathematics
1 answer:
topjm [15]3 years ago
6 0
Box Plot has less variability in the data.  We can determine this by the distances between the beginning of the data to the end (range) and the distances between lower quartile and the upper quartile (interquartile range).

Box #1
Range - 30
IQR - 15

Box #2
Range - approximately 23
IQR - approximately 9

Box #2 has less variation in the data because the distances between these 2 ranges are smaller meaning the data is closer together.
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Provide a solution for the following equation: 3x + 2y=4
shtirl [24]

Answer:

One solution is to find x and y by doing the following:

Step-by-step explanation:

Let's solve for x.

3x+2y=4

Step 1: Add -2y to both sides.

3x+2y+−2y=4+−2y

3x=−2y+4

Step 2: Divide both sides by 3.

x=-2/3y+4/3

Lets solve for y.

3x+2y=4

Step 1: Add -3x to both sides.

3x+2y+−3x=4+−3x

2y=−3x+4

Step 2: Divide both sides by 2.

y= -3/2x+2

7 0
3 years ago
If 3x is one factor of 3x^2-9x, what is the other factor?
Rudik [331]
The answer is:  " (x² − 3) " .
_________________________________
Explanation:
_________________________________

Given:  3x² <span>− 9x ;  factor out a "3x" ; 
_________________________________
 
   </span>→  3x (x² − 3) ;
_________________________________
     The answer is:  " (x² − 3) " .
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7 0
3 years ago
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
sergeinik [125]
The answer is B. 822.42 miles, because if you take the 304.6 and multiply is by 2.7 it will give you 822.42 as your answer. Hope this helped! please mark this as brainiest ^^
6 0
3 years ago
Read 2 more answers
The pressure applied to a leverage bar varies inversely as the distance from the object. If 150 pounds is required for a distanc
AlexFokin [52]

Answer:

500 pounds

Step-by-step explanation:

Let the pressure applied to the leverage bar be represented by p

Let the distance from the object be represented by d.

The pressure applied to a leverage bar varies inversely as the distance from the object.

Written mathematically, we have:

p \propto \dfrac{1}{d}

Introducing the constant of proportionality

p = \dfrac{k}{d}

If 150 pounds is required for a distance of 10 inches from the object

  • p=150 pounds
  • d=10 inches

150 = \dfrac{k}{10}\\\\k=1500

Therefore, the relationship between p and d is:

p = \dfrac{1500}{d}

When d=3 Inches

p = \dfrac{1500}{3}\\\implies p=500$ pounds

The pressure applied when the distance is 3 inches is 500 pounds.

4 0
3 years ago
every story gets an additional 10% off the already discounted price. if an employee buys an item with an original price of $40,
ANTONII [103]
36.
 Convert 10% to .1, (10 divided by 100)
 then multiply 40 times .1
then subtract 4 by 40
=36

5 0
3 years ago
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