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nikklg [1K]
3 years ago
8

98 POINTS AND WILL MARK BRAINLIEST given the equation of the line y=-x-2. What is the equation of the image after a 270 degree r

otation about the orgin.
Name the relationship (parrell, perpendicular, neither) 98 POINTS AND WILL MARK BRAINLIEST
Mathematics
2 answers:
MAXImum [283]3 years ago
7 0

Answer:

2/4 of 360 , Perpendicular

Step-by-step explanation:

(Took the test and got this right)

If my answer qualifies please mark brainliest!

Tomtit [17]3 years ago
6 0

perpendicular and 1/2 of 360

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A student has $5.00 to spend on a poster, paint, and stickers. The total cost for the
babunello [35]

Answer:

2.8+.55x=5 x=4

Step-by-step explanation:

5-2.8=2.2

2.2/.55=4

4 0
2 years ago
If n is an odd integer, which equation can be used
soldi70 [24.7K]

Answer:

3,-1,-5 = -3

Step-by-step explanation:

The 3 odd numbers cannot be all negative ,the result would be  less than -3

5 0
3 years ago
Solve for x x=750+125.75x
olga2289 [7]
X=750+125.75x
subtract to variable (x) on one side
x-125.75x=750+125.75x-125.75x
-124.75x=750
divide -124.75 to get variable (x) by itself
-124.75x/-124.75=750/-124.75
x=-3000/499
or
x=-6 6/499
or
x=-6.01202

7 0
3 years ago
Hexagon DEFGHI is translated on the coordinate plane below to create hexagon D'E'F'G'H'I':
SVETLANKA909090 [29]

Answer:

(x, y)→(x − 8, y − 7)

Step-by-step explanation:

If we take the hexagon DEFGHI coordinates and apply the rule (x, y)→(x − 8, y − 7) we get:

D (2, 5) → (2 - 8, 5 - 7) = (-6, -2) which corresponds to point D'

E (5, 5) → (5 - 8, 5 - 7) = (-3, -2) which corresponds to point E'

F (6, 3) → (6 - 8, 3 - 7) = (-2, -4) which corresponds to point F'

G (5, 1) → (5 - 8, 1 - 7) = (-3, -6) which corresponds to point G'

H (2, 1) → (2 - 8, 1 - 7) = (-6, -6) which corresponds to point H'

I (1, 3) → (1 - 8, 3 - 7) = (-7, -4) which corresponds to point I'

6 0
3 years ago
Read 2 more answers
Find all possible values of α+
const2013 [10]

Answer:

\rm\displaystyle  0,\pm\pi

Step-by-step explanation:

please note that to find but α+β+γ in other words the sum of α,β and γ not α,β and γ individually so it's not an equation

===========================

we want to find all possible values of α+β+γ when <u>tanα+tanβ+tanγ = tanαtanβtanγ</u><u> </u>to do so we can use algebra and trigonometric skills first

cancel tanγ from both sides which yields:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =  \tan( \alpha )  \tan( \beta )  \tan( \gamma )  -  \tan( \gamma )

factor out tanγ:

\rm\displaystyle  \tan( \alpha )  +  \tan( \beta ) =   \tan( \gamma ) (\tan( \alpha )  \tan( \beta ) -  1)

divide both sides by tanαtanβ-1 and that yields:

\rm\displaystyle   \tan( \gamma ) =  \frac{ \tan( \alpha )  +  \tan( \beta ) }{ \tan( \alpha )  \tan( \beta )    - 1}

multiply both numerator and denominator by-1 which yields:

\rm\displaystyle   \tan( \gamma ) =   -  \bigg(\frac{ \tan( \alpha )  +  \tan( \beta ) }{ 1 - \tan( \alpha )  \tan( \beta )   } \bigg)

recall angle sum indentity of tan:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( \alpha  +  \beta )

let α+β be t and transform:

\rm\displaystyle   \tan( \gamma ) =   -  \tan( t)

remember that tan(t)=tan(t±kπ) so

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm k\pi )

therefore <u>when</u><u> </u><u>k </u><u>is </u><u>1</u> we obtain:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta\pm \pi )

remember Opposite Angle identity of tan function i.e -tan(x)=tan(-x) thus

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha  -\beta\pm \pi )

recall that if we have common trigonometric function in both sides then the angle must equal which yields:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm \pi

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ \pm \pi  }

<u>when</u><u> </u><u>i</u><u>s</u><u> </u><u>0</u>:

\rm\displaystyle   \tan( \gamma ) =    -\tan(   \alpha   +\beta \pm 0 )

likewise by Opposite Angle Identity we obtain:

\rm\displaystyle   \tan( \gamma ) =    \tan(   -\alpha   -\beta\pm 0 )

recall that if we have common trigonometric function in both sides then the angle must equal therefore:

\rm\displaystyle  \gamma  =      -   \alpha   -  \beta \pm 0

isolate -α-β to left hand side and change its sign:

\rm\displaystyle \alpha  +  \beta  +   \gamma  =  \boxed{ 0  }

and we're done!

8 0
3 years ago
Read 2 more answers
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