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beks73 [17]
3 years ago
9

Someone please help me will give BRAILIEST!!!!!

Mathematics
2 answers:
Step2247 [10]3 years ago
5 0
Answer is 7/2 because the # of earthquakes increased by 7 and the number of years increased by 2.
Ghella [55]3 years ago
3 0
It's the third one 7/2
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A hardware store owner has 1,152 screws. If she wants to put them in packages of 32, how many packages can she make?
melomori [17]

Answer:

i think 36

Step-by-step explanation:

1152 / 32= 36

5 0
3 years ago
What is 20% of 120 ??? HELP ME
maksim [4K]

Answer:

24

Step-by-step explanation:

3 0
3 years ago
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A rectangle has a length that is 7 inches less that twice it's width. The area of the rectangle is 72 square inches. Write an eq
Nitella [24]

Answer: 2x^2-7x=72 , where  x= width of the rectangle ( in inches).

Step-by-step explanation:

Let x= width of the rectangle ( in inches).

Then its length =  2x-7 ( in inches).

Area of rectangle = Length × width

= (2x-7) × (x)

= 2x × x -7 ×x

= 2x²-7x

The area of the rectangle is 72 square inches.

\Rightarrow\ 2x^2-7x=72

Hence, the equation that represents the given situation :

2x^2-7x=72

7 0
3 years ago
Esther wants to know if the number of words on a page in her language arts book is generally more than the number of words on a
kykrilka [37]
Answer: The correct answer is "No, because there is a lot of variability in the language arts book data."

The mean of the language arts book is higher than the mean of the social studies book, however, there is a lot of variability in the language arts book. This means that the language arts book could actually be lower than the social studies book. It is not likely but it could happen.
7 0
4 years ago
Read 2 more answers
Suppose a simple random sample of size nequals36 is obtained from a population with mu equals 74 and sigma equals 6. ​(a) Descri
OlgaM077 [116]

Part a)

The simple random sample of size n=36 is obtained from a population with

\mu = 74

and

\sigma = 6

The sampling distribution of the sample means has a mean that is equal to mean of the population the sample has been drawn from.

Therefore the sampling distribution has a mean of

\mu = 74

The standard error of the means becomes the standard deviation of the sampling distribution.

\sigma_ { \bar X }  =  \frac{ \sigma}{ \sqrt{n} }  \\ \sigma_ { \bar X }  =  \frac{ 6}{ \sqrt{36} }  = 1

Part b) We want to find

P(\bar X \:>\:75.9)

We need to convert to z-score.

P(\bar X \:>\:75.9)  = P(z \:>\: \frac{75.9 - 74}{1} )  \\  = P(z \:>\: \frac{75.9 - 74}{1} ) \\  = P(z \:>\: 1.9) \\  = 0.0287

Part c)

We want to find

P(\bar X \: < \:71.95)

We convert to z-score and use the normal distribution table to find the corresponding area.

P(\bar X \: < \:71.95)  = P(z \: < \: \frac{71.9 5- 74}{1} )  \\  = P(z \: < \: \frac{71.9 5- 74}{1} ) \\  = P(z \: < \:  - 2.05) \\  = 0.0202

Part d)

We want to find :

P(73\:

We convert to z-scores and again use the standard normal distribution table.

P( \frac{73 - 74}{1} \:< \: z

5 0
3 years ago
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