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2 years ago

The tempeture of chicken soup is 192.7 degrees F. As it cools the tempeture of the soup decreases 2.3F per minute.

Mathematics

1 answer:

IrinaK [193]2 years ago

6 0

Answer:

Step-by-step explanation:

To find the answer to Part A, we can turn this into a simple equation:

192.7 - (2.3 times 25) = temperature, the missing value.

So therefore, after 25 minutes pass, the temperature is equal to

192.7 - 57.5, or:

135.2 = Answer to Part A.

Now, onto Part B. We can use another equation!

192.7 - 2.3x = 100.7

Now, we must solve the given equation, first by taking 100.7 from each side:

192.7 - 2.3x = 100.7

-100.7 -100.7

We are now left with: 92 - 2.3x = 0 - we must now add 2.3x to 2.3x and 0, giving us this:

92 = 2.3x, which is equivalent to 920 = 23x, if that is what you prefer to solve.

To give us our missing value (x), we can divide 920 by 23, giving us: x = 40. This is the answer to Part B: 40 minutes.

I hope this was really helpful! Tell me if you need any more help.

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If Upper X overbar equals 62, Upper S equals 8, and n equals 36, and assuming that the population is normally distributed, c

marishachu [46]

Answer:

The 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X=62$ represent the sample mean

$\mu$ population mean (variable of interest)

s=8 represent the sample standard deviation

n=36 represent the sample size

Part a: Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=36-1=35$

Since the Confidence is 0.99 or 99%, the value of $\alpha=0.01$ and $\alpha/2 =0.005$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.005,35)".And we see that $t_{\alpha/2}=2.72$

Now we have everything in order to replace into formula (1):

$62-2.72\frac{8}{\sqrt{36}}=58.373$

$62+2.72\frac{8}{\sqrt{36}}=65.627$

So on this case the 99% confidence interval would be given by (58.373;65.627)

We are 99% confident that the true mean for the variable of interest is between 58.373 and 65.627.

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