Question

A rectangle has a length that is 7 inches less that twice it's width. The area of the rectangle is 72 square inches. Write an equation that represents this solution.

Answer 1

Answer: $2x^2-7x=72$ , where  x= width of the rectangle ( in inches).

Step-by-step explanation:

Let x= width of the rectangle ( in inches).

Then its length =  2x-7 ( in inches).

Area of rectangle = Length × width

= (2x-7) × (x)

= 2x × x -7 ×x

= 2x²-7x

The area of the rectangle is 72 square inches.

$\Rightarrow\ 2x^2-7x=72$

Hence, the equation that represents the given situation :

$2x^2-7x=72$