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Tanya [424]
2 years ago
11

PLS HELP ME ASAP FOR 42!! (MUST SHOW WORK!!) + LOTS OF POINTS!! *no calculator* *best if show work on picture*

Mathematics
1 answer:
Tpy6a [65]2 years ago
4 0
It's 2.5 bc it goes up by 2.5 everytime
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When 37299 is divided by a number , the quotient is 298 and the remainder is 49. what is the number?​
alisha [4.7K]

Answer:

\huge\boxed{125}

Step-by-step explanation:

n-\text{a number}\\\\298n+49=37299\qquad|\text{subtract 49 from both sides}\\\\298n+49-49=37299-49\\\\298n=37250\qquad|\text{divide both sides by 298}\\\\\dfrac{298n}{298}=\dfrac{37250}{298}\\\\n=125

8 0
2 years ago
Read 2 more answers
Find the area of the parallaogram to the nearest tenth
GuDViN [60]

Answer:

sorry I think yr question is incomplete.

u forget to add picture.

<h3>stay safe healthy and happy.</h3>

6 0
3 years ago
I need help with a math problem: y x 6 for y = 2/3
STALIN [3.7K]

Answer:

the answer is 4.

Step-by-step explanation:

2×6= 12

12/3=4

3 0
3 years ago
29. Find the height of the trapezoid. Use this height to find the area. (A =
harkovskaia [24]

Answer:

<em>The area of the trapezium is 168</em>

Step-by-step explanation:

<u>Area of a Trapezoid</u>

Given a trapezoid of parallel bases b1 and b2, and height h, the area is calculated with the formula:

\displaystyle A=\frac{b_1+b_2}{2}h

The trapezoid in the figure has b1=15 and b2=27. We need to find the height. If we focus on triangle BCD, we can calculate the height as the distance EC by using the Pythagora's Theorem:

10^2=EC^2+BC^2

The side BC can be found as half the difference of the bases:

BC=\frac{27-15}{2}=6

Solving for EC:

EC^2=10^2-6^2=100-36=64

EC=\sqrt{64}=8

Now we have the height, calculate the area:

\displaystyle A=\frac{15+27}{2}*8

\displaystyle A=\frac{42}{2}*8

A = 168

The area of the trapezium is 168

5 0
2 years ago
A. y = -1.33x; 2.67<br> B. y = -0.75x; 1.50<br> C. y = 1.33x; -2.67<br> D. y = 0.13x; -0.25
Crazy boy [7]

Answer:

c is the correct answer for this problem

Step-by-step explanation:


7 0
3 years ago
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