ANSWER: SECOND OPTION
Do the opposite of PEMDAS.
Do SADMEP
(If you don’t know what that means; it’s an order of operation. S is for subtraction, A is for addition, D is for division, E is for exponents, P is for parenthesis.)
The first thing you should do it multiply 2 on each sides, then divide k on each side, and then square root on each side. The square root with cancel the squared (2) on X
Answer:
Step-by-step explanation:
Let's multiply the 2 by the other 2.
Let's combine it all together
Since we already know that is , we add it to the y.
Hope this helps!
Y = mx + b
plug in m and b
y = (3)x + (10)
hope this helps
Start by taking out a common factor.
x^10
x^10(x^6 - 2x^5 - x^4 + 4x^3 - x^2 - 2x + 1) = 0
So far we know that D won't work.
x - 1 is a factor because putting 1 in for the xs in the expression inside the brackets gives 0 Now you need to do a division. I'm going to assume you can do that.
Using division, I get
x^5 - x^4 - 2x^3 + 2x^2 + x - 1 Now divide x - 1 into this mess again. You get
x^4 - 2x^2 + 1 which factors into
(x^2 - 1)(x^2 - 1) which factors into
(x - 1)(x + 1)(x - 1)(x + 1) = 0
The first two divisions add (x -1)(x - 1)
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So we have (x - 1) with a multiplicity of 4 and (x + 1) with a multiplicity of 2
or x = 1 with a multiplicity of 4 and x = -1 with a multiplicity of 2 and x = 0
with a multiplicity of 10
That's the answer.
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