$\left \{ {{y+4x=12} \atop {3y=8-12x}} \right. \\\\ \left \{ {{y=12-4x} \atop {3y=8-12x}} \right. \\\\3(12-4x)=8-12x\\\\36-12x=8-12x\\\\-12x+12x=8-36\\\\0\neq28\\\\There\ are\ no\ solutions.$

6 0

4 years ago

A truck rental company rents a moving truck One Day by charging $39 + 0.09 per mile write a linear equation that relates the cos

Ivanshal [37]

Answer:

$(a)\ c(x) = 39 + 0.09 x$

$(b)\ \$53.4$

Step-by-step explanation:

Given

$Base\ Charge = \$39$

$Rate = 0.09$ per mile

Solving (a): Linear Equation

The total charges (c(x)) is: the base charge + the rate * number of miles (x).

So, we have:

$c(x)= 39 + 0.09 * x$

$c(x) = 39 + 0.09 x$

Solving (b): Cost of rent, if miles = 160

This implies that x = 160

So, we have:

$c(x) = 39 + 0.09 x$

$c(160) = 39 + 0.09 *160$

$c(160) = 39 + 14.4$

$c(160) = 53.4$

7 0

3 years ago