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jarptica [38.1K]
3 years ago
14

How to get the area of the lion?check the enclosed photo please!

Mathematics
1 answer:
Alborosie3 years ago
5 0
The area of the lion is 6m

Because: This shape is difficult to find the area of so lets break it up into a square an 2 triangles. The squares dimensions are 2mx2m, to find the area of this we multiple them together to get, 4m. Next the triangles are the same dimensions so finding one, we find the other. The dimensions of these are 2mx1m. To find the area of a triangle you multiple the 2 sides (not the diagonal side) and divide by 2. 2x1 is 2, divided by 2 is 1. So the area of both of the triangles is 1. Now we just need to add all of these together. 4m+1m+1m= 6m
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Answer:

Perimeter = 44.67

Step-by-step explanation:

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3 years ago
Solve the given problem. Zara is six years older than half Gary’s age. If Gary is four years old, how old is Zara?
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A rectangular package sent by a postal service can have a maximum combined length and girth (perimeter of a cross sectio) of 108
Morgarella [4.7K]

Answer:

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

Step-by-step explanation:

This is a optimization with restrictions problem.

The restriction is that the perimeter of the square cross section plus the length is equal to 108 inches (as we will maximize the volume, we wil use the maximum of length and cross section perimeter).

This restriction can be expressed as:

4x+L=108

being x: the side of the square of the cross section and L: length of the package.

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If we express L in function of x using the restriction equation, we get:

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We replace L in the volume formula and we get

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To maximize the volume we derive and equal to 0

\dfrac{dV}{dx}=-4*3x^2+108*2x=0\\\\\\-12x^2+216x=0\\\\-12x+216=0\\\\12x=216\\\\x=216/12=18

We can replace x to calculate L:

L=108-4x=108-4*18=108-72=36

The maximum volume of the package is obtained with a cross section of side 18 inches and a length of 36 inches.

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