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swat32
3 years ago
6

A school received a $7,563 grant for new supplies to be evenly distributed among 18 classroom teachers. How much money will each

classroom teacher receive, to the nearest dollar?
Mathematics
2 answers:
NikAS [45]3 years ago
3 0

Answer:

Step-by-step explanation:

so there is $ 7563 that needs to be evenly distributed among 18 people

so were gonna do a little division to solve this...

7563 / 18 = 420.166 rounded to the nearest dollar = $ 420 <===

sattari [20]3 years ago
3 0

Answer:

$420

Step-by-step explanation:

$7,563/18

=$420.1667

=$420.17 (to the nearest dollar means to the nearest full dollar and since 17      cents is not up to 50, you remove it )

= $420

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Hyperloop, a new mode of travel, aims to reach a speed of 170170 \dfrac{\text{m}}{\text{s}} s m ​ . This is 50\%50% less than th
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Answer:

Speed of sound is 340 meter per second.

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Let the speed of sound = x meter per second.

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8 0
3 years ago
Read 2 more answers
If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?
bixtya [17]

Answer:

T_{2} = 200

Step-by-step explanation:

Given

Geometry Progression

T_1 = 500

T_4 = 32

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

T_n = ar^{n-1}

For first term: Tn = 500 and n = 1

500 = ar^{1-1}

500 = ar^{0}

500 = a

a = 500

For fought term: Tn = 32 and n = 4

32 = ar^{4-1}

32 = ar^3

Substitute 500 for a

32 = 500 * r^3

Make r^3 the subject

r^3 = \frac{32}{500}

r^3 = 0.064

Take cube roots

\sqrt[3]{r^3} = \sqrt[3]{0.064}

r  = \sqrt[3]{0.064}

r = 0.4

Using:  T_n = ar^{n-1}

n = 2     r = 0.4     and a = 500

T_{2} = 500 * 0.4^{2-1}

T_{2} = 500 * 0.4^1

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<em>Hence, the second term is 200</em>

5 0
3 years ago
16, 4,1,...<br> Find the 6th term
Vlada [557]

Let's see what to do...

_________________________________

Step (1)

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To find the 6th term just need to put the following parameters in the above sequence.

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_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

3 0
3 years ago
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