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Likurg_2 [28]
3 years ago
11

Please help thank you!! will give brainlist!​

Mathematics
1 answer:
ratelena [41]3 years ago
5 0

Answer:

the third one

Step-by-step explanation:

y+8= 4(x-3)

y+8= 4x-12

y= 4x-20

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The dimensions of a rectangle are √50a^3b^2 and √200a^3. What is the students error?
bearhunter [10]

Answer:

The student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

Step-by-step explanation:

The formula to determine the Perimeter of a rectangle of width w and length l is expressed as:

P = 2l + 2w

In other words, the perimeter can be determined by multiplying the length and width by 2 and adding the result.

In our case, the dimensions of a rectangle are \sqrt{50a^3b^2}  and  \sqrt{200a^3}\:\:.

Here is the student's solution:

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

                                 =30ab\sqrt{2a}          

The student made an error in calculating 30ab\sqrt{2a}+20a\sqrt{2a} , because 30ab\sqrt{2a}+20a\sqrt{2a} are not like terms.

Hence, 30ab\sqrt{2a}+20a\sqrt{2a} can not be simplified to 30ab\sqrt{2a}

Therefore, the student incorrectly simplified 30ab\sqrt{2a}+20a\sqrt{2a} .

Thus, option D is correct.

<u></u>

<u></u>

<u>Here is the correct Solution:</u>

2\sqrt{50a^3b^2}+2\sqrt{200a^3}=2\cdot 5ab\sqrt{2a}+2\cdot 10a\sqrt{2a}

                                 =10ab\sqrt{2a}+20a\sqrt{2a}

7 0
3 years ago
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Answer is Centroid 100%
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The top and bottom lines are parallel. what is the value of X?
nataly862011 [7]

Answer:

B, the answer is B or C believe me

Step-by-step explanation:

5 0
2 years ago
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Need help checking my answers thanks!!
Hitman42 [59]

Answer:

They are correct good job!

Step-by-step explanation:

3 0
3 years ago
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I have no clue how to do this n it’s in f tmrw pls help lol
Fofino [41]

Area = w × h

w = width

h = height

6 0
3 years ago
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