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vredina [299]
3 years ago
8

Find the distance between the two points S(-5, -2) and T(-3, 4).

Mathematics
1 answer:
Dafna1 [17]3 years ago
5 0

Step-by-step explanation:

Hey there!

The points are; S(-5,-2) and T(-3,4).

Using distance formula to find the distance between two points.

d =  \sqrt{( {x2 - x1)}^{2}  + ( {y2 - y1)}^{2}  }

Put all values.

d =  \sqrt{  {( - 3 + 5)}^{2}  +  {(4 + 2)}^{2} }

Simplify it.

d =  \sqrt{ {(2)}^{2} +  {(6)}^{2}  }

d =  \sqrt{4 + 36}

d =  \sqrt{40}

Therefore the distance between two points is root 40 units Or 6.324 units.

Or, you can write as 6 units after rounding off.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

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keeping in mind that in a parallelogram the diagonals bisect each other, namely cut each other into two equal halves.  Check the picture below.

\stackrel{GH}{3x-4}~~ = ~~\stackrel{HE}{5y+1}\implies 3x=5y+5\implies x=\cfrac{5y+5}{3} \\\\[-0.35em] ~\dotfill\\\\ \stackrel{DH}{x+1}~~ = ~~\stackrel{HF}{3y}\implies \stackrel{\textit{substituting "x" in the equation}}{\cfrac{5y+5}{3}+1~~ = ~~3y}

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<u>/3   /3</u>

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I hope this helped you!! Have a great day c:

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