3 years ago

How do I solve please help me out

Mathematics

1 answer:

adoni [48]3 years ago

8 0

You by combing like terms

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Suppose that two cards are randomly selected from a standard 52-card deck. (a) what is the probability that the first card is

Savatey [412]

(a) without replacement:
P(S)=13/52=1/4
P(SS)=(1/4)*(12/51)=1/17
Probability of selecting two spades without replacement is 1/17.

(b) with replacement
P(S)=13/52=1/4
P(SS)=(1/4)(13/52)=1/16
Probability of selecting two spades with replacement is 1/16.

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3 years ago

Sam leases a car for 24 months. The car will cost him $7,000 if he decides to buy it at the end of the lease. What term describe

astra-53 [7]

25t + 45m is the traval of the car

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3 years ago

Read 2 more answers

Evaluate the expression.<br><br> -2 + 49 divided (-7)

Ann [662]

Answer:

-9

Step-by-step explanation:

+49/-7=-7

-2-7=-9

3 0

2 years ago

Can you see an easy way to work out the value of <img src="https://tex.z-dn.net/?f=%5Csqrt%7B%201%5E3%20%2B%202%5E3%20%2B%203%5E

Lina20 [59]

We have the sum of cubes identity

$a^3 + b^3 = (a + b) (a^2 - ab + b^2)$

and observing that 1 + 4 = 2 + 3, we have

$1^3 + 4^3 = (1 + 4) (1^2 - 4 + 4^2) = 5 \times 13$

and

$2^3 + 3^3 = (2 + 3) (2^2 - 6 + 3^2) = 5 \times 7$

Then

$\sqrt{1^3+2^3+3^3+4^3+5^3} = \sqrt{5\times13 + 5\times7 + 5\times5^2} = \sqrt{5 \times (20 + 25)} \\\\ ~~~~~~~~ = \sqrt{5^2 \times (4 + 5)} = \sqrt{5^2\times9} = \sqrt{5^2\times3^2} = 5\times3 = \boxed{15}$