Multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
<h3>How to expand quadratic equations?</h3>
We want to expand the quadratic equation given as;
(x + 2)(4x - 3)
Multiplying out gives us;
4x² + 8x - 3x - 6
⇒ 4x² + 5x - 6
Thus, we can conclude that multiplying out the equation (x + 2)(4x - 3) and arranging in descending powers order gives us the quadratic form as; 4x² + 5x - 6
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Answer:
Step-by-step explanation:
Let number of large pizzas be l and number of small be s.
<u>Then we have equations:</u>
- l + s = 100
- 16l + 11s = 1550
<u>From the first equation, we get l = 100 - s and substitute in the second equation:</u>
- 16(100 - s) + 11s = 1550
- 1600 - 16s + 11s = 1550
- 5s = 1600 - 1550
- 5s = 50
- s = 10
Number of small pizzas is 10
Answer:
S’ (-5,-3)
T’ (4,-6)
U’ (-3,-7)
Step-by-step explanation:
Basically, we want to apply the given transformation rule of the axes to get the coordinates of the images
The rule is that we subtract 1 from the x-coordinates and also subtract 5 from the y-coordinates
Thus, we proceed as follows;
S’ = (-4-1, 2-5) = (-5,-3)
T’ = (5-1, -1-5) = (4,-6)
U’ = (-2-1,-2-5) = (-3,-7)
Answer:
e) The mean of the sampling distribution of sample mean is always the same as that of X, the distribution from which the sample is taken.
Step-by-step explanation:
The central limit theorem states that
"Given a population with a finite mean μ and a finite non-zero variance σ2, the sampling distribution of the mean approaches a normal distribution with a mean of μ and a variance of σ2/N as N, the sample size, increases."
This means that as the sample size increases, the sample mean of the sampling distribution of means approaches the population mean. This does not state that the sample mean will always be the same as the population mean.