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4 years ago

What is the equation of the function in slope-intercept form?

Mathematics

2 answers:

tensa zangetsu [6.8K]4 years ago

6 0

I think the answer is 2/3 +3 but I’m not entirely sure

VARVARA [1.3K]4 years ago

3 0

Answer:

y=2/3x+3

Step-by-step explanation:

slope-intercept form is written as y=mx+b

To find your slope, or m, pick 2 points along the line. I chose (0, 3) and (3, 5)

Then use the slope formula, y,2-y,1 / x,2-x,1

**y,2 is my abbreviation for y sub 2, or the y-coordinate of your second coordinate pair, and so on

5-3 / 3-0

2/3

m=2/3

To fid your y-intercept, or b, find the coordinate at which the line intersects the y-axis. This is (0, 3). The take the y-coordinate from this, or 3. Thus b=3

Plug in m and b to slope intercept from

So, y=2/3x+3

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Plz help!............

prisoha [69]

Answer:

Step-by-step explanation:

B/c 0 is included in the range since it the origin of the graph and it then goes to negative infinity. This is why y has to be less than equal to 0 which means 0 is included and graph goes to negative infinity.

7 0

3 years ago

Read 2 more answers

Find all points on the x-axis that are 14 units from the point (6,-7) All points on the x-axis that are 14 units from the point

Maksim231197 [3]

Answer: $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

or (18.124,0) and ( -6.124,0) are the required points.

Step-by-step explanation:

Let (x,0) be the point on x -axis that are 14 units from the point (6,-7) .

Then by distance formula , we have

$\sqrt{(x-6)^2+(0-(-7))^2}=14\ \ \ [\ \because distance=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}]$

Taking square on both the sides , we get

$(x-6)^2+7^2=14^2\\\\\Rightarrow\ x^2+6^2-2(6)x+49=196\\\\\Rightarrow\ x^2+36-12x=147\\\\\Rightarrow\ x^2-12x=111\\\\\Rightarrow\ x^2-12x-111=0$

Using quadratic formula : $x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x=\dfrac{12\pm\sqrt{(-12)^2-4(1)(-111)}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{144+444}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{588}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm\sqrt{2^2\times7^2\times3}}{2}\\\\\Rightarrow\ x=\dfrac{12\pm14\sqrt{3}}{2}\\\\\Rightarrow\ x=6\pm7\sqrt{3}$

so, $(6+7\sqrt{3},0)\text{ and }(6-7\sqrt{3},0)$ are the required points.

since $\sqrt{3}=1.732$

so, $(6+7(1.732),0)\text{ and }(6-7(1.732),0)$ are the required points.

i.e. (18.124,0) and ( -6.124,0) are the required points.

3 0

3 years ago

Help me out pleaseeeeee!!

makkiz [27]

Answer:

y=1/2r hope i helped

4 0

3 years ago

Solve for x -5(x+1)+3x-3=-14

ASHA 777 [7]

Answer:

x= 3

Step-by-step explanation:

Hope I get brainliest!

6 0

3 years ago

Use the distributive property to simplify the expressions. 1B. -3(9x-q) 2B. 2(12+5p) 3b. -7(-8y+7) 4b. 10(2+7c) 5b. -8(7+11k) 6b

Debora [2.8K]

1B: -3(9x-q)
-27x + 3q

Step 1: Distribute the -3 to the 9x to get -27x.
Step 2: Distribute the -3 to the -q.

2B: 2(12+5p)
24 + 10p

Step 1: Distribute the 2 to the 12 to get 24.
Step 2: Distribute the 2 to the 5p to get 10p.

3B: -7(-8y+7)
56y - 49

Step 1: Distribute the -7 to the -8y to get 56y.
Step 2: Distribute the -7 to the 7 to get -49.

4B: 10(2+7c)
20 + 70c

Step 1: Distribute the 10 to the 2 to get 20.
Step 2: Distribute the 10 to the 7c to get 70c.

5B: -8(7+11k)
-56 - 88k

Step 1: Distribute the -8 to the 7 to get -56.
Step 2: Distribute the -8 to the 11k to get -88k.

6B: -(3-7u)
-1(3-7u)
-3 + 7u

Step 1: Place a 1 after the negative symbol to symbolize -1.
Step 2: Distribute the -1 to the three to get -3.
Step 3: Distribute the -1 to the -7u to get 7u.

7B: -6(5p + s)
-30p - 6s

Step 1: Distribute the -6 to the 5p to get -30p.
Step 2: Distribute the -6 to the s to get -6s.

:) :D

8 0

3 years ago

What is the equation of the function in slope-intercept form?​

What is the equation of the function in slope-intercept form?