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2 years ago

Consider the recursively defined function below.

Mathematics

2 answers:

ddd [48]2 years ago

6 0

Answer:

-5.25, -3.5, -1.75, 0, 1.75

The recursive relation tells you this is an arithmetic sequence with a common difference of 1.75. Each term is 1.75 more than the one before.

To find the 2nd term, add 1.75 to the first term: -5.25 + 1.75 = -3.5

To find the 3rd term, add 1.75 to the second term: -3.5 + 1.75 = -1.75

To find the 4th term, add 1.75 to the third term: -1.75 + 1.75 = 0

To find the 5th term, add 1.75 to the forth term: 0 + 1.75 = 1.75

Dvinal [7]2 years ago

5 0

Answer:

-5.25, -3.5, -1.75, 0, 1.75

Step-by-step explanation:

The recursive relation tells you this is an arithmetic sequence with a common difference of 1.75. Each term is 1.75 more than the one before.

To find the 2nd term, add 1.75 to the first term: -5.25 + 1.75 = -3.5

To find the 3rd term, add 1.75 to the second term: -3.5 + 1.75 = -1.75

To find the 4th term, add 1.75 to the third term: -1.75 + 1.75 = 0

and so on ...

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Wanda opened a savings account 20 years ago with a deposit of $3,150.37. The account has an interest rate of 4.1% compounded dai

Aleksandr [31]

$\bf ~~~~~~ \stackrel{daily}{\textit{Continuously Compounding Interest Earned Amount}}\\\\
A=Pe^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to& \$3150.37\\
r=rate\to 4.1\%\to \frac{4.1}{100}\to &0.041\\
t=years\to &20
\end{cases}
\\\\\\
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how much interest is there? well, A - 3150.37.

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2 years ago

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What is 2/3 of the product of 3/8and 16

MA_775_DIABLO [31]

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2 years ago

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Josh Pruitt worked 48.75 hours.

leva [86]

For this case, as Josh worked more than 40 hours, he was able to receive a payment
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3 years ago

Find the monthly payment for the loan. Finance $500,000 for an apartment complex with a 12.3% 10-year loan.

Marina86 [1]

Using it's formula, it is found that the monthly payments for the loan of the apartment is of $7,260.50.

<h3>What is the monthly payment formula?</h3>

It is given by:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

In which:

P is the initial amount.

r is the interest rate.

n is the number of payments.

In this problem, the parameters are given as follows:

P = 500000, r = 0.123, n = 12 x 10 = 120.

Hence:

r/12 = 0.123/12 = 0.01025.

Then, the monthly payments will be of:

$A = P\frac{\frac{r}{12}\left(1 + \frac{r}{12}\right)^n}{\left(1 + \frac{r}{12}\right)^n - 1}$

$A = 500000\frac{0.01025(1+0.01025)^{120}}{(1+0.01025)^{120} - 1}$

A = 7260.50.

More can be learned about the monthly payment formula at brainly.com/question/26267630

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2 years ago