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bija089 [108]
3 years ago
9

18 8 13 7 Find the area of the white granite area in the picture above.

Mathematics
1 answer:
GaryK [48]3 years ago
8 0

Answer: 178

Step-by-step explanation:

18x13

234 area of white granite

8x7

56 area of blue granite

234-56 to find the area of the white granite

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What is the y-intercept ** write as a ordered pair.​
Ahat [919]

Answer:

Y intercept is at (0,0)

4 0
3 years ago
On a coordinate plane, 2 right triangles are shown. The first triangle has points A (negative 1, 3), B (negative 1, 1), C (3, 1)
drek231 [11]

Answer:

  • B and E

Step-by-step explanation:

<u>Given</u>

  • ΔABC ⇒ A(- 1, 3), B(- 1, 1), C(3, 1)
  • ΔA'B'C' ⇒ A'(2, - 2), B'(2, - 4), C'(6, - 4)

<u>Comparing the coordinates of the corresponding vertices, we see the difference:</u>

  • x → x + 3, y →  y - 5

It means the ΔABC has been translated 3 units right and 5 units down

Correct answer choices are B and E

8 0
3 years ago
Read 2 more answers
How can I find the slope and Y- intercept for each equation
mixer [17]
Answer:

You plug in numbers into the y=mx+b equation and solve for which ever one you are finding for.
m=slope
x=x intercept
b=y intercept
apply the numbers to this equation and solve or x
7 0
3 years ago
Which table represents a direct variation function? A table with 6 columns and 2 rows. The first row, x, has the entries, negati
IceJOKER [234]

Answer:

The correct option is;

A table with 6 columns and 2 rows. The first row, x, has entries, negative 3, negative 1, 2, 5, 10. The second row, y, has entries, negative 7.5, negative 2.5, 5.0, 12.5, 25

Please find attached the graphs of the table data

Step-by-step explanation:

Each of the given table data of in the tables are analysed to find direct variation;

Table 1

x,               -3,                 -1,                 2,                5,                10

y,              -4.5,              -3.0,             -1.5,             0.0,              1.5              

-4.5/-3  = 1.5 ≠ -3.0/-1 = 3

No direct variation

Table 2      

x,             -5.5,               -4.5,            -3.5,            -2.5,             -1.5

y,              10,                   8,                 6,              4,                  2

10/(-5.5) = -20/11  ≠ 8/(-4.5) = -16/9

However, 10/(-5.5 + 0.5) = -2 = 8/(-4.5 + 0.5) = -2

Adjusted direct variation

Table 3              

x,              -5.5,               -5.5,             -5.5,           -5.5,            -5.5

y,              -3,                    -1,                 2,                5 ,              10                  

-3/(-5.5) ≠ -1/-5.5

No direct variation

Table 4

x,              -3,                    -1,                2,                  5,             10

y,              -7.5,                 -2.5,            5.0 ,              12.5,         25  

 -7.5/-3 = 2.5 = -2.5/(-1) = 5.0/2 = 12.5/5 =25/10

Direct variation exists        

8 0
4 years ago
Read 2 more answers
As a​ follow-up to a report on gas​ consumption, a consumer group conducted a study of SUV owners to estimate the mean mileage f
kondor19780726 [428]

Answer:

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

Step-by-step explanation:

Our sample size is 96.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

df = 96-1 = 95

Then, we need to subtract one by the confidence level \alpha and divide by 2. So:

\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 95 and 0.025 in the t-distribution table, we have T = 1.9855.

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

s = \frac{5.6}{\sqrt{96}} = 0.57

Now, we multiply T and s

M = T*s = 1.9855*0.57 = 1.31

For the lower end of the interval, we subtract the mean by M. So 19.6 - 1.31 = 18.29

For the upper end of the interval, we add the mean to M. So 19.6 + 1.31 = 20.91

The 95​% confidence interval estimate for the mean highway mileage for SUVs is (18.29mpg, 20.91mpg).

8 0
4 years ago
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