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Elza [17]
2 years ago
6

A circle is divided into 3 equal parts. What is the total angle measure of 1 part?

Mathematics
1 answer:
fenix001 [56]2 years ago
4 0

Answer:

120 degrees each

Step-by-step explanation:

360 degress divided by 3 = 120

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Find the area of a circle with radius, r = 5.7m.
goldenfox [79]

Answer:

the area of the circle is 102.11 square metres

6 0
3 years ago
Calvin's rug covers 1/8 of the floor space in his bedroom how much floor space would be covered if Calvin had four rugs of that
djverab [1.8K]

Answer:

I dont really know what this is asking but i think it would be 4/8 or 1/2

Step-by-step explanation:

Im sorry if its wrong

7 0
2 years ago
How do I write an equation for each parabolas?
fredd [130]

Step-by-step explanation:

  1. In the first parabola it opens on the left and the equation of parabola can be expressed as,

              in vertical component <u>(y)² = (-) a (x-h)² + k</u>

cause  the parabola is horizontal and it opens on the left.

          2. In the second parabola the vertex opens on the right and hence the      equation cane be given as,

    in vertical component <u>(y)² = a (x-h)² + k</u>

cause the parabola is horizontal and opens on the right.

       3. the third equation is given as,

        in horizontal component<u> (x²) =</u> <u> (-) a (x-h)² + k</u>

since the parabola is vertical and opens down.

        4. the fourth equation is given as,

        in the horizontal component  <u>(x)² = a (x-h)² + k</u>

since the parabola is vertical and opens up.

             

   

7 0
2 years ago
What is the d value in the following arithmetic sequence? -7, -2, 3, 8, …
gizmo_the_mogwai [7]

Answer:

+5

Step-by-step explanation:

You add five to -7 you get -2 add five to -2 you get 3 and so on.

4 0
3 years ago
Read 2 more answers
A random sample of 23 items is drawn from a population whose standard deviation is unknown. The sample mean isx⎯ ⎯ x¯ = 840 and
gayaneshka [121]

Answer:

(832.156, \ 847.844)

Step-by-step explanation:

Given data :

Sample standard deviation, s = 15

Sample mean, \overline x = 840

n = 23

a). 98% confidence interval

$\overline x \pm t_{(n-1, \alpha /2)}. \frac{s}{\sqrt{n}}$

$E= t_{( n-1, \alpha/2 )} \frac{s}{\sqrt n}}

$t_{(n-1 , \alpha/2)} \frac{s}{\sqrt n}$

$t_{(n-1, a\pha/2)}=t_{(22,0.01)} = 2.508$

∴ $E = 2.508 \times \frac{15}{\sqrt{23}}$

  $E = 7.844$

So, 98% CI is

$(\overline x - E, \overline x + E)$

(840-7.844 ,  \ 840+7.844)

(832.156, \ 847.844)

4 0
2 years ago
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