You always start by simplifying.
6b-49=2<span>(</span>b-3) becomes 6b-49=2b-6
From there you can group the b's together by subtracting 2b from both sides, leaving you with 4b-49=-6
Now you can get the b's alone by adding 49 (to cancel out -49) to both sides, giving you 4b=43, You're still trying to get b by itself, so what you'll do is divide both sides by 4, giving you b=10.75
The ratio 9/15 and 6/15 form a proportion
The probability that the sum of Michelle's rolls is 4 is 0.083
∴ P(A)=0.083
Step-by-step explanation:
Given that Michelle is rolling two six-sided dice, numbered one through six.
To find the probability that the sum of her rolls is 4:
∴ n(s)=36
Let P(A) be the probability that the sum of her rolls is 4
Then the possible rolls with sums of 4 can be written as
n(A)=3
The probability that the sum of her rolls is 4 is given by
=0.083
∴ P(A)=0.083
∴ the probability that the sum of Michelle's rolls is 4 is 0.083
-please give brainliest if correct!
Answer:
i'd say it's x=6
Step-by-step explanation:
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