In classical mechanics there are three base dimensions. length is one of them. what are the other two?

1 answer:

4 0

In classical mechanics, the three base dimensions are length which is already given in the question, mass and time. Mass refers to the amount of substance present and this is usually expressed in g, kg, lbs, and others. Time is the measured moments that have passed from different events and usually expressed in seconds.

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This is (compound) probability: Picking two numbers from 1-10 and getting a multiple of 3 both times.

NemiM [27]

Answer:

There are 10 counters in the bag and you want the 4

As their is only one for the probability is

1/10

There are now 9 counters left in the bag.

You only want the even ones , which are 2 6 8 and 10 ( four has been taken out)

There are only four even counters in the bag of nine counters so the probability is

4/9

As you want both of these to occur, you need to multiply them

1/10 x 4/9 = 49/90

Step-by-step explanation:

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What is the probability of getting either a three or a jack when drawing a single card from a deck of 52 cards?

Elden [556K]

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Convert 23 miles to feet. (1 mile -= 5280 feet)

Makovka662 [10]

Answer:

121, 440 ft

Step-by-step explanation:

5280*23= 121, 440 ft

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Which is a correct first step in solving 5 - 2x < 8x - 3?

Natasha2012 [34]

Answer:

5< 10x -3

add like terms first

make sure X's are on one side and numbers on the other

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3 years ago

Read 2 more answers

the vertex of this parabola is at (3,5). When the y-value is 6, the x-value is -1. What is the coefficient of the squared term i

otez555 [7]

Now, assuming is a vertical parabola, so the squared variable is the "x", let's do some checking.

$\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=3\\
k=5
\end{cases}\implies y=a(x-3)^2+5
\\\\\\
\textit{we also know that }
\begin{cases}
y=6\\
x=-1
\end{cases}\implies 6=a(-1-3)^2+5
\\\\\\
1=a(-4)^2\implies 1=16a\implies \cfrac{1}{16}=a$

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3 years ago