Ask question

Ask question

All categories

4 years ago

6

In classical mechanics there are three base dimensions. length is one of them. what are the other two?

1 answer:

Helen [10]4 years ago

4 0

In classical mechanics, the three base dimensions are length which is already given in the question, mass and time. Mass refers to the amount of substance present and this is usually expressed in g, kg, lbs, and others. Time is the measured moments that have passed from different events and usually expressed in seconds.

You might be interested in

Which numbers are equivalent to 3/10

Sedbober [7]

Answer:

Multiply numerator and denominator with same number to gwt the answers . There are infinitely many numbers

3/10 × 2/2 = 6/20

3/10 × 5/5 = 15/50

3/10 × 10/10 = 30/100

And so on

8 0

3 years ago

5 - (x + 5) > -2(x+4)

Vinil7 [7]

Answer:

5-(1+5)= -1

-2(1+4)=-10

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

What is the coolest hair and eye color combination? Mine is Red hair and blue eyes... That's because I have red hair and blue ey

marysya [2.9K]

Answer:

Hi how are you doing today Jasmine

6 0

3 years ago

Read 2 more answers

Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .

sergey [27]

Step 1) Divide the figure into separate shapes

Long rectangle: 27 x 5

Triangle: 3 x 4

Middle rectangle: 15 x 7

Small rectangle: 6 x 3

Step 2) Find the area of each shape

Long rectangle: A = 27 x 5 = 135

Triangle: A = 1/2 x 3 x 4 = 6

Middle rectangle: A = 15 x 7 = 105

Small rectangle: 6 x 3 = 18

Step 3) Add all of the areas together

A = 135 + 6 + 105 + 18 = 264 square feet

Hope this helps! :)

8 0

4 years ago

CON PROCESOS POR FAVOR

labwork [276]

Answer:

$\dfrac{149}{40}$

$\dfrac{38}{15}$

Step-by-step explanation:

$(\dfrac{7}{8} + \dfrac{4}{5}) - (\dfrac{9}{20} + \dfrac{-5}{2}) =$

$= (\dfrac{7}{8} \times \dfrac{5}{5} + \dfrac{4}{5} \times \dfrac{8}{8}) - (\dfrac{9}{20} + \dfrac{-5}{2} \times \dfrac{10}{10})$

$= (\dfrac{35}{40} + \dfrac{32}{40}) - (\dfrac{9}{20} + \dfrac{-50}{20})$

$= \dfrac{67}{40} - (-\dfrac{41}{20})$

$= \dfrac{67}{40} + \dfrac{41}{20} \times \dfrac{2}{2}$

$= \dfrac{67}{40} + \dfrac{82}{40}$

$= \dfrac{149}{40}$

$(-\dfrac{6}{4} + \dfrac{3}{2}) + (\dfrac{6}{5} + \dfrac{4}{3}) =$

$= (-\dfrac{3}{2} + \dfrac{3}{2})+ (\dfrac{6}{5} \times \dfrac{3}{3} + \dfrac{4}{3} \times \dfrac{5}{5})$

$= 0 + \dfrac{18}{15} + \dfrac{20}{15}$

$= \dfrac{38}{15}$

4 0

2 years ago