In classical mechanics there are three base dimensions. length is one of them. what are the other two?

1 answer:

4 0

In classical mechanics, the three base dimensions are length which is already given in the question, mass and time. Mass refers to the amount of substance present and this is usually expressed in g, kg, lbs, and others. Time is the measured moments that have passed from different events and usually expressed in seconds.

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simon says that to find the area of a trapezoid, you can multiply the height by the top base and the height by the bottom base.

denis-greek [22]

He is correct
basically you have
h times base1+h times bsae 2 all divided by 2
that equals
(hb1+hb2)/2
if we undistribute h using distributive property which is ab+ac=a(b+c)
(h)(b1+b2)/2

if you split the trapezoid in half with a horizontal line that passes through the halfway point of the height and take those two shapes and put them side by side and cut the triangles off the ends and add them, you will see why this is true

the reason is becuase you can get to the area formula from that is height times (b1+b2)/2

3 0

3 years ago

Read 2 more answers

A hemisphere has an area of 256 pi cm^2. What is its volume?

Amanda [17]

$\bf \begin{array}{llll}
\textit{surface area of a sphere}\\\\
A=4\pi r^2
\\\\\\
\textit{a hemisphere is half that}\\\\
A=\cfrac{4\pi r^2}{2}\implies A=2\pi r^2
\end{array}\qquad r=radius
\\\\\\
\textit{now, we know the area is }256\pi \implies 256\pi =2\pi r^2
\\\\\\
\cfrac{256\pi }{2\pi }=r^2\implies \sqrt{128}=r\implies \boxed{8\sqrt{2}=r}
\\\\
-----------------------------\\\\$

$\bf \textit{volume of a sphere}\\\\
V=\cfrac{4}{3}\pi r^3\qquad r=radius
\\\\\\
\textit{a hemisphere is half that}\\\\
V=\cfrac{\frac{4}{3}\pi r^3}{2}\implies V=\cfrac{\frac{4\pi r^3}{3}}{\frac{2}{1}}\implies V=\cfrac{4\pi r^3}{3}\cdot \cfrac{1}{2}
\\\\\\
V=\cfrac{2\pi r^3}{3}
\\\\\\
\textit{now, we know the radius is }8\sqrt{2}\implies V=\cfrac{2\pi (8\sqrt{2})^3}{3}
\\\\\\
V=\cfrac{2\pi (8^3\sqrt{2^3})}{3}\implies V=\cfrac{2\pi \cdot 512\cdot 2\sqrt{2}}{3}
\\\\\\
\boxed{V=\cfrac{2048\pi \sqrt{2}}{3}}$

7 0

3 years ago

PLEASE HELP...........

shtirl [24]

Answer:

increases

decreases but stays above 0.

Step-by-step explanation:

Increases without bound. You are going left which means that x is getting smaller and smaller (large negatives are very small).

As x increases without bounds, f(x) approaches 0 but does not go minus.

5 0

3 years ago

Keith collected the names and ages of all of his classmates and organized them in the ordered pair (name, age).

erastova [34]

Answer:

It is both a relation and a function.

Step-by-step explanation:

Keith collected the names and ages of all of his classmates and organized them in the ordered pair (name, age).

Here, if we consider the name as the input and age is the output, then each and every different input there is a single output.

Because a single person can not have more than one age.

Therefore, it is both a relation and a function. (Answer)

7 0

3 years ago

-3(4x+3)+4(6x+1)=43 how do I solve it

Gala2k [10]

Solve for x:
4 (6 x + 1) - 3 (4 x + 3) = 43
-3 (4 x + 3) = -12 x - 9:
-12 x - 9 + 4 (6 x + 1) = 43
4 (6 x + 1) = 24 x + 4:
24 x + 4 - 12 x - 9 = 43
Grouping like terms, 24 x - 12 x - 9 + 4 = (24 x - 12 x) + (4 - 9):
(24 x - 12 x) + (4 - 9) = 43
24 x - 12 x = 12 x:
12 x + (4 - 9) = 43
4 - 9 = -5:
12 x + -5 = 43
Add 5 to both sides:
12 x + (5 - 5) = 5 + 43
5 - 5 = 0:
12 x = 43 + 5
43 + 5 = 48:
12 x = 48
Divide both sides of 12 x = 48 by 12:
(12 x)/12 = 48/12
12/12 = 1:
x = 48/12
The gcd of 48 and 12 is 12, so 48/12 = (12×4)/(12×1) = 12/12×4 = 4:
Answer: x = 4

3 0

4 years ago