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Rzqust [24]
3 years ago
14

18 of the last 30 cars that passed by you were black. what is the probability the next car will be black. (0.18, 0.6, or 0.30)

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
3 0
18 divided by 30 is 0.6. So I would say that B, or 0.6, is the correct answer.
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1.name two streets that intersect but do not appear to be perpendicular
trasher [3.6K]
1. Maple and Oak (touch but without a right angle)
2. Maple and Birch (will never meet and are same distance from each other forever)
6 0
3 years ago
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We are given AB ∥ DE. Because the lines are parallel and segment CB crosses both lines, we can consider segment CB a transversal
ohaa [14]

Answer: AAA similarity.


Step-by-step explanation:  CB is the transversal for the parallel lines AB and DE, and so by transverse property, we have ∠CED ≅ ∠CBA. Similarly, CA acts as a tranversal for the same pair of parallel lines AB and DE and using the same property, we can have ∠CDE ≅ ∠CAB. Now, in triangles CED and ABC, we have

∠CED ≅ ∠CBA,

∠CDE ≅ ∠CAB

and

∠DCE ≅ ∠ACB [same angle]

Hence, by AAA (angle-angle-angle) similarity,

△CED ~ △ABC.

Thus, the correct option is AAA similarity.


8 0
3 years ago
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What is the domain of y=tan x?<br><br>​
IrinaVladis [17]

The domain of the function y=tan(x) ) is all real numbers except the values where cos(x) is equal to 0 , that is, the values π/2+πn for all integers n . The range of the tangent function is all real numbers.

8 0
2 years ago
What is the answer for x 7x+24+19x+33
Semmy [17]

Steps to solve:

7x + 24 + 19x + 33

~Combine like terms

26x + 57

Best of Luck!

3 0
3 years ago
Read 2 more answers
2 3/8 - 4 1/2 + 3 1/8 - (1/2)
UkoKoshka [18]

let's convert the mixed fractions to improper fractions firstly.

\bf \stackrel{mixed}{2\frac{3}{8}}\implies \cfrac{2\cdot 8+3}{8}\implies \stackrel{improper}{\cfrac{19}{8}}~\hfill \stackrel{mixed}{4\frac{1}{2}}\implies \cfrac{4\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{9}{2}} \\\\\\ \stackrel{mixed}{3\frac{1}{8}}\implies \cfrac{3\cdot 8+1}{8}\implies \stackrel{improper}{\cfrac{25}{8}} \\\\[-0.35em] ~\dotfill

\bf \cfrac{19}{8}-\cfrac{9}{2}+\cfrac{25}{8}-\cfrac{1}{2}\implies \stackrel{\textit{using an LCD of 8}}{\cfrac{(1)19-(4)9+(1)25-(4)1}{8}}\implies \cfrac{19-36+25-4}{8} \\\\\\ \cfrac{4}{8}\implies \cfrac{1}{2}

8 0
3 years ago
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