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k0ka [10]
3 years ago
5

Line segment AB is on the coordinate plane and has endpoints at A(-5,3) and B(1,8). What is the length of the line segment to th

e nearest hundredth?
A) 30.5 B) 11.0 C) 7.81 D) 3.32
Mathematics
2 answers:
AlladinOne [14]3 years ago
8 0

Answer:

C) 7.81

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

<em>Identify</em>

Point A(-5, 3)

Point B(1, 8)

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                         \displaystyle d = \sqrt{(1--5)^2+(8-3)^2}
  2. [√Radical] (Parenthesis) Subtract:                                                                   \displaystyle d = \sqrt{(6)^2+(5)^2}
  3. [√Radical] Evaluate exponents:                                                                      \displaystyle d = \sqrt{36+25}
  4. [√Radical] Add:                                                                                                 \displaystyle d = \sqrt{61}
  5. [√Radical] Evaluate:                                                                                         \displaystyle d = 7.81025
  6. Round:                                                                                                               \displaystyle d \approx 7.81
skelet666 [1.2K]3 years ago
6 0

Answer:

AB = 7.81

Step-by-step explanation:

Distance between 2 points = sqrt( (x2 - x1)^2 + (y2 - y1)^) )

x2 = - 5

x1 = 1

y2 = 3

y1 = 8

D = sqrt( -5 - 1)^2 + (3 - 8)^2 )

D = sqrt( (-6)^2 + (-5)^2 )

D = sqrt( (36 + 25)

D = sqrt( 61)

D = 7.81

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