Greatest common factor for 21 and 40

Chef Selena is making her special dish that requires pasta, sauce, and onions. She has 5 1/8 pounds of pasta, 6 pounds of sauce,

arlik [135]

Answer:

$\text{Total Weight of Food Made}, x=5\frac{1}{8}+6+4\frac{7}{8}\\\text{Number of Servings}, y=x \div \frac{1}{2}$

Step-by-step explanation:

The Weight of Ingredients to be used by Chef Selena are:

$5\frac{1}{8}$ pounds of pasta,
6 pounds of sauce; and
$4\frac{7}{8}$ pounds of onions.

Total Weight of Food Made, x

$=5\frac{1}{8}+6+4\frac{7}{8}\\=5+6+4+\frac{1}{8}+\frac{7}{8}\\=16 \: Pounds$

Since each serving is $\frac{1}{2} Pounds$

Number of Servings of her dish, y

$16 \div \frac{1}{2}\\ =32 \: Servings$

The two equations needed to solve the problem are therefore:

$\text{Total Weight of Food Made}, x=5\frac{1}{8}+6+4\frac{7}{8}\\\text{Number of Servings}, y=x \div \frac{1}{2}$

4 0

3 years ago

Can you please help with 19&23? 19 says write an expression to represent the perimeter. Thanks!

Valentin [98]

the perimeter is simply the sum of all its sides.

(6a+8)+(12a)+(6a+8)+(10a-4)

34a + 16 - 4

34a + 12.

7 0

3 years ago

In a sample of 70 stores of a certain company, 62 violated a scanner accuracy standard. It has been demonstrated that the condi

uysha [10]

Answer:

We need at least 243 stores.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error of the interval is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

For this problem, we have that:

$n = 70, p = \frac{62}{70} = 0.886$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

Determine the number of stores that must be sampled in order to estimate the true proportion to within 0.04 with 95% confidence using the large-sample method.

We need at least n stores.

n is found when M = 0.04. So

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.04 = 1.96\sqrt{\frac{0.886*0.114}}{n}}$