Answer:
cosB = 21/75, tanB = 72/21
Step-by-step explanation:
Here, we can use pythagoras to figure out all sides. 75^2-72^2 = 21^2. So, we have sides with lengths 21, 72, and 75. We are given that sinB = 72/75. The definition of sin is opposite of hypotenuse. So, the opposite of angle B is side CA and the hypotenuse is BA. This allows us to find that BC is the 21 length side. The cos of an angle is adjacent over hypotenuse. In this case, it is BC/BA which is 21/75. similarly, Tan is opposite over adjacent or 72/21. And we are done. Those are the values. TO remember these, use the acronym:
SOH CAH TOA. S refers to sin and OH refers to opposite over hypotenuse. Similarly C is cos, A is adjacent, and H is hypotenuse, and then T is tan, o is opposite and A is adjacent.
Answer:
1 hour later , 21 pages read
Step-by-step explanation:
x hour later they will read the same number of pages
Tori: 16 + 5x
cora: 13 + 8x
16 + 5x = 13 + 8x
minus 5x each sides: 16 = 13 + 3x
minus 13 each sides: 3 = 3x
divide 3 each sides: x = 1
1 hour later both of them will read 16 + 5 x 1 = 21 pages
check cora: 13 + 8 x 1 = 21
It would be 9
0=20
1=29
2=? So that would be 38
3=47
and so forth
Answer:
8 pi yd.
Step-by-step explanation:
The circumference of a circle can be calculated as follows:
c = 
Where r is the radius of the circumference.
So in our case:
c = 
yd.
9514 1404 393
Answer:
3) x = 55, y = 123, z = 123
4) x = 276°
Step-by-step explanation:
<h3>3)</h3>
Angles P and Q are alternate interior angles, so are congruent.
P = Q
3x -42° = 2x +13°
x = 55° . . . . . . . . . . . add 42°-2x
Then Q = 2x +13 = 2(55°) +13° = 123°.
Angles Y, P, Q, and Z are all congruent, so all have the same measure.
Y = Z = 123°
__
<h3>4)</h3>
If you draw a horizontal line parallel to AB and CD through point O, then small angle POQ is divided into parts that are congruent with angles APO and CQO. That is, small angle POQ = 48° +36° = 84°.
Large angle POQ is then 360° -84° = 276°
