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lara31 [8.8K]
3 years ago
14

In a group of 25 people, only three languages are spoken – English, Spanish and German. If there is at least one person who spea

ks all the three languages, how many people can interact with each other in English and German? 4 people speak two languages but do not speak Spanish One fifth of the group speaks more than one language.
Mathematics
1 answer:
Brut [27]3 years ago
5 0

Answer:

x + a=5

Step-by-step explanation:

Let

number of people who speak only English = E

the number of people who speak only German = G

the number of people who speak only Spanish = S

the number of people who speak only English & German but not Spanish = x

the number of people who speak only English & Spanish but not German = y

the number of people who speak only German & Spanish but not English = z;

the number of people who speak only German & Spanish & English = a

Find the the value of (x + a).

Statement 1: 4 people speak two languages but do not speak Spanish.

x = 4.

x+a

Value for a is unknown.

(x + a). Insufficient.

Statement 3: One-fifth of the group speaks more than one language.

x + y + z + a

= 25/5

= 5

value of (x + a) unknown

Insufficient.

Putting (1) and (2) together

x + y + z + a = 5

x = 4 and a=1,

we have only one possible solution from

x + y + z + a = 5

x + a

= 4 + 1

= 5.

Sufficient.

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astra-53 [7]
The mean is calculated by adding up all of the given numbers and dividing by the number of numbers.

Lets, for ease of understanding, say that the first three number were 64...

Mean=(64+64+64)/3=192/3=64

Now, lets solve for the mean where 'x' is the unknown fourth number and 128 is the mean. (since, the answer said that when the fourth number was added the mean, 64, was doubled '64*2=128')

128=(64+64+64+x)/4
128=(192+x)/4
Multiply both sides by 4
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subtract 192 from both sides
320=x

The missing number is 320..


Now lets double check our work.

Mean=(64+64+64+320)/4=512/4=128

Answer=320
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