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3 years ago

HELP!!!!!!

Mathematics

2 answers:

strojnjashka [21]3 years ago

7 0

Answer:

Um, no lo sé, lo siento, solo necesito los puntos

Step-by-step explanation:

Nataly [62]3 years ago

7 0

Answer:

False; the slope is 2/3 and the y intercept is 1/4

I hope this is good enough:

You might be interested in

Write an equation of the line passing through (-6, 1) that is perpendicular to the line 2x -5y = 2

Bess [88]

Answer:

y= -5/2 x + 14 (point slope form)

2y+5x=28 (standard form)

Step-by-step explanation:

Perpendicular lines met the following condition

m1*m2=-1 (the product of their slopes is -1)

To obtain m2, the slope of our desired line lets first re arrange the equation of the first line. 2x-5y=2, so. 2x-2=5y.

Isolating y, leads the following, result: y= 2/5 x - 2/5

m1=2/5

m2 is =-5/2

The equation of our desired line is the following

y=mx+b, we have m, which is -5/2, but still need to find value for b.

Lets now evaluate the above equation in the given point (-6,1).

1=-6 * -5/2 + b.

b=14.

Now we can say the equation that our desired line is

y= -5/2 x + 14 (point slope form)

Or... If we group variables 'x' and 'y' together

y+5/2 x = 14, we want integer coefficients, so lets multiply this expression by 2, to obtain the following:

2y+5x=28

4 0

3 years ago

URGENT!!! Amy, on a jog, runs in a straight line for 3 miles. She then changes direction, heading 50 degrees to the right and ru

Mariana [72]

Answer:

8.2500000000 miles

Step-by-step explanation:

I drew a triangle to illustrate the reference triangle.

So, Amy ran from summit A for 3 miles then turned to her right by 50 degrees (creating angle B of 130 degrees), and runs for another 6 miles.

Based on the Cosines Law, we have:

$cos(B) = \frac{c^{2} + a^{2} - b^{2} }{2 * c * a}$

If we isolate b, we have the following formula.

$b = \sqrt{a^{2} + c^{2} - 2 * a * c * cos(B) } \\ \\b = \sqrt{6^{2} + 3^{2} - 2 * 6 * 3 * cos(130) } = 8.25$

So, as she stops at summit C, she's 8.25 miles away from her starting point.

4 0

3 years ago

(-8,-4)&(2,-9) fint the distance between each pair of points

Makovka662 [10]

Answer:

$5 \sqrt{5}$

Step-by-step explanation:

We want to find the distance between (-8,-4) and (2,-9).

We use the distance formula:

$d = \sqrt{ {(x_2-x_1)^2} +(y_2-y_1)^2 }$

We substitute the coordinates to get:

$d = \sqrt{ {(2- - 8)^2} +( - 9 - - 4)^2 }$

We simplify to obtain:

$d = \sqrt{ {(2 + 8)^2}+( - 9 + 4)^2 }$

Add the numbers within the parenthesis to get:

$d = \sqrt{ {(10)^2}+( -5)^2 }$

Find the squares of the numbers under the radical

$d = \sqrt{ {100}+25}$

$d = \sqrt{125} = 5 \sqrt{5}$

7 0

3 years ago

Find the product of 9^8*9^6

miss Akunina [59]

9^8= 9x9x9x9x9x9x9x9= 43046721

9^6= 9*9*9*9*9*9=531441

43046721*531441= 228767133233961

5 0

3 years ago

Which of these data sets is symmetrical?

Savatey [412]

I believe it is A, because the one's place are equal on both side of the median.

7 0

3 years ago