Answer
given,
y(x,t)= 2.20 mm cos[( 7.02 rad/m )x+( 743 rad/s )t]
length of the rope = 1.33 m
mass of the rope = 3.31 g
comparing the given equation from the general wave equation
y(x,t)= A cos[k x+ω t]
A is amplitude
now on comparing
a) Amplitude = 2.20 mm
b) frequency =
f = 118.25 Hz
c) wavelength
d) speed
v = 105.84 m/s
e) direction of the motion will be in negative x-direction
f) tension
T = 27.87 N
g) Power transmitted by the wave
P = 0.438 W
Answer:
i. 0.34
ii. 0.4
iii. 1700 w/m²
iv. 2211.36 w/m²
Explanation:
Given that
Irradiation of the plate, G = 2500 w/m²
Reflected rays, p = 500 w/m²
Emissive power, E = 1200 w/m²
See attachment for calculations
Given Information:
Current = Ii = 7.2 A
Number of turns inner coil = Ni = 140
Number of turns outer coil = No = 180
Radius inner coil = ri = 0.015 m
Radius outer coil = ro = 0.023 m
Required Information:
outer coil current = Io = ?
Answer:
Io = 8.6 A
Step-by-step explanation:
We have two coils, subscript i denotes inner coil and o denotes the outer coil.
According to the Biot-Savart Law
B = μ₀IN/2r
we will equate the inner and outer magnetic fields
Bi=Bo
μ₀IiNi/2ri = μ₀IoNo/2ro
μ₀ and 2 cancels out
Io = Ii*Ni*ro/No*ri
Io = 7.2*140*0.023/180*0.015
Io = 8.6 A
Therefore, a current of 8.6 A is needed to flow in opposite direction so that the magnetic field is opposite and the net magnetic field will be zero.