The distance the lower spring is stretched from its equilibrium length is 45cm because the weight is 3x as much as the reference spring and the spring constant is the same.
<span>2) The force the bottom spring exerts on the mass is its weight (=mg) PLUS 10.8kg x 3.8m/s^2 = 133N </span>
<span>3) The distance the upper spring is extended from its unstretched length when not accelerated is 15cm </span>
<span>4) Rank the distances the springs are extended from their unstretched lengths: </span>
<span>c) x1 < x2 < x3 </span>
<span>5) The distance the MIDDLE spring is extended from its unstretched length when not accelerated is 45cm </span>
<span>6) Finally, the elevator is moving downward with a velocity of v = -3.4 m/s and also accelerating downward at an acceleration of a = -2.1 m/s2. </span>
<span>a)speeding up </span>
<span>because the v and a are in the same direction</span>
They are experiencing the pull of leaving the atmosphere
Answer:
A
Explanation:
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Answer:

Given:
Mass (m) = 3.0 kg
Uniform speed (v) = 20 m/s
Length of string (r) = 40 cm = 0.4 m
To Find:
Tension in the string (T)
Explanation:
Tension (T) is the string will be equal to centripetal force (
).

Substituting value of m, v & r in the equation:


Tension in the string (T) = 3 kN
Answer with explanation:
We are given that
Mass of ball,
75 g=
1 kg=1000 g
Height,

Horizontal velocity,
Mass of plate
a.Initial velocity of plate,
Velocity before impact=
Where 
Velocity after impact,
According to law of conservation of momentum

Substitute the values



Velocity of plate=1.69 m/s
b.Initial energy=
Final energy=
Final energy=
Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J