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lesya692 [45]
3 years ago
11

5) Unlike the five big mass extinctions in the geological record, the current wave of extinctions is

Physics
2 answers:
xz_007 [3.2K]3 years ago
7 0

Answer:

B.Volcanism

Explanation:

Cause every time the current wave moves is causes and eruption

Sladkaya [172]3 years ago
3 0
Although I may be wrong, A- Human activity is the answer.
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A single mass m1 = 3.6 kg hangs from a spring in a motionless elevator. The spring is extended x = 15.0 cm from its unstretched
umka21 [38]
The distance the lower spring is stretched from its equilibrium length is 45cm because the weight is 3x as much as the reference spring and the spring constant is the same. 

<span>2) The force the bottom spring exerts on the mass is its weight (=mg) PLUS 10.8kg x 3.8m/s^2 = 133N </span>

<span>3) The distance the upper spring is extended from its unstretched length when not accelerated is 15cm </span>

<span>4) Rank the distances the springs are extended from their unstretched lengths: </span>
<span>c) x1 < x2 < x3 </span>

<span>5) The distance the MIDDLE spring is extended from its unstretched length when not accelerated is 45cm </span>

<span>6) Finally, the elevator is moving downward with a velocity of v = -3.4 m/s and also accelerating downward at an acceleration of a = -2.1 m/s2. </span>
<span>a)speeding up </span>
<span>because the v and a are in the same direction</span>
8 0
3 years ago
When astronauts travel to the moon, their bodies experience a lower gravitational pull than on Earth. Which type of pull are the
postnew [5]
They are experiencing the pull of leaving the atmosphere

3 0
4 years ago
Read 2 more answers
The physiological need include:
harina [27]

Answer:

A

Explanation:

food for energy, security from theft and privacy

5 0
3 years ago
A 3.0kg mass tied to a string
dem82 [27]

Answer:

\boxed{\sf Tension \ in \ the \ string \ (T) = 3 \ kN}

Given:

Mass (m) = 3.0 kg

Uniform speed (v) = 20 m/s

Length of string (r) = 40 cm = 0.4 m

To Find:

Tension in the string (T)

Explanation:

Tension (T) is the string will be equal to centripetal force (\sf F_c).

\boxed{ \bold{ T = F_c  =  \frac{m {v}^{2} }{r} }}

Substituting value of m, v & r in the equation:

\sf \implies T =  \frac{3 \times  {20}^{2} }{0.4}  \\  \\  \sf \implies T = \frac{3 \times 400}{0.4}  \\  \\  \sf \implies T =3 \times 1000 \\  \\  \sf \implies T =3000 \: N \\  \\ \sf \implies T =3 \: kN

\therefore

Tension in the string (T) = 3 kN

5 0
3 years ago
1 A 75-g ball is projected from a height of 1.6 m with a horizontal velocity of 2 m/s and bounces from a 400-g smooth plate supp
Tanzania [10]

Answer with explanation:

We are given that  

Mass of ball,m_1=75 g=\frac{75}{1000}=0075kg

1 kg=1000 g

Height,h_1=1.6 m

h_2=0.6 m

Horizontal velocity,v_x=2 m/s

Mass of platem_2=400 g=\frac{400}{1000}=0.4 kg

a.Initial velocity of plate,u_2=0

Velocity before impact=u_1=\sqrt{2gh_1}=\sqrt{2\times 9.8\times 1.6}=5.6m/s

Where g=9.8 m/s^2

Velocity after impact,v_1=\sqrt{2gh_2}=\sqrt{2\times 9.8\times 0.6}=3.4m/s

According to law of conservation of momentum  

m_1u_1+m_2u_1=-m_1v_1+m_2v_2

Substitute the values  

0.075\times 5.6+0=-0.075\times 3.4+0.4v_2

0.4v_2=0.075\times 5.6+0.075\times 3.4

v_2=\frac{0.075\times 5.6+0.075\times 3.4}{0.4}=1.69 m/s

Velocity of plate=1.69 m/s

b.Initial energy=\frac{1}{2}m_1v^2_x+m_1gh_1=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 1.6=1.326 J

Final energy=\frac{1}{2}m_1v^2_x+m_1gh_2+\frac{1}{2}m_2v^2_2

Final energy=\frac{1}{2}(0.075)(2^2)+0.075\times 9.8\times 0.6+\frac{1}{2}(0.4)(1.69)^2=1.162 J

Energy lost due to compact=Initial energy-final energy=1.326-1.162=0.164 J

6 0
3 years ago
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