The answer is a pushing policy. A promotion policy intended at distribution centers to inspire their advertising of a product or service area to their customers. For instance, a pushing policy might be used by an manufacturing business to market to a distribution channel of traders and dealers to get their help in receiving their customers to buy its product.
Answer:
b. Accept Project A and reject Project B.
Explanation:
To verify project viability at a required return rate of 16%, simply calculate the project's net present value at a rate of 16%. If the NPV is positive, then the project should be accepted, otherwise it should be rejected.
Project A:

Project A should be accepted.
Project B:

Project B should be rejected.
Answer:
The answer is E. a unit of account; a medium of exchange
Explanation:
Because they allows different things to be compared against each other; for example, goods, services, assets, liabilities, labour income, expenses.
A unit of account is a monetary unit of measurement of value or cost.
And the second is a medium of exchange because $3 is being used to buy cone. It exchanged money for cone.
Answer:
33.94%
Explanation:
The computation of stock's expected price 5 years is shown below:-
Stock price = $26
Required return = 12%
Growth rate = 7%
Current dividend per share = Stock price × (Required return - Growth rate) ÷ (1 + Growth rate)
= $26 × (12% - 7%) ÷ (1 + 7%)
= $26 × 5% ÷ 1.07
= $1.21
Stock price in 5 years = Expected dividend ÷ (required return - Growth rate)
Expected dividend = $1.21 × (1 + 7%)^5
= $1.21 × 1.402551731
= $1.697
Stock price in 5 years = $1.697 ÷ (12% - 7%)
= $1.697 ÷ 5%
= 33.94%
Answer:
Explanation:
I think your question is missed of key information, allow me to add in and hope it will fit the original one. Please have a look at the attached photo.
Given:
- Cost $71 per linear foot
- Budge $34080 for those walls
Let X is the the length
Let Y is the width
From the photo, we can see that
(4X + 6Y)*71 = 34080
<=> (4X + 6Y) = 480
<=> Y = 80 -
X
The are of the rectangular industrial warehouse:
A(X) = 3Y*X
<=> A(X) = 3(80 -
X )X
<=>A(X) = (240-2X)X = 240X -
So A'(X) = 240 - 4X
Let A'(X) = 0, we have:
240 - 4X = 0
<=> X = 60
=> Y =(80 -
X ) = 80 -
*60 = 40
So the dimension to maximize total area is: 60 in length and 40 in width