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lubasha [3.4K]
3 years ago
7

The residents of Bucktown, Illinois, place their trash at the curb each Wednesday morning to be picked up by Municipal Crews. Ex

perience shows the total amount of trash put out has a normal distribution with a mean of 35 tons and a standard deviation of 9 tons. Crews of full-time city employees assigned to trash collection collect trash. Each group can collect five tons of trash per working day. The city has plenty of trucks of the kind used for trash collection. The marginal cost of operating one trash collection crew for one working day, including both personnel-related costs and truck-related costs, is reckoned at $625. Whatever trash remains at the end of the workday must be collected that evening by an outside contractor who charges $650 per ton. How many crews should the city assigned to trash collection? Treat the number of Crews as a continuous variable.
Business
1 answer:
svetoff [14.1K]3 years ago
8 0

Answer: 8.56crews

Explanation:

To get critical fractile probability SL,

We stock up the local trash collection capacity.Cost of overstocking by 1 ton =MC = 625/5 = $125Cost of understocking by 1 ton = additional cost of using outside trash pick up = MB = $650-$125 = $5

SL = Prob(RQ) = MB /( MB + MC) = 525/(125 + 525) = 0.8077 appropriate # of crews = 8.56 crews

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<span>The extent to which the income from individual transactions is affected by fluctuations in foreign exchange values is known as Transaction Exposure.</span><span />
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Ben learns that the company was going to be laying off several employees over the next several months. He knew that the rumor mi
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Answer:

D. Call an all staff meeting and give everyone the news at once.

Explanation:

Instead of letting the rumors spread throughout the company, what Ben is supposed to do is have a meeting with his entire staff and let all of them know at once what's going on. This way, he will be clear and direct and won't allow for gossip to spread throughout his company and he himself will address the issue head-on. This way he won't leave room for misinterpretation as he will explain what is going to happen.

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3 years ago
Lang Co. issued bonds with detachable common stock warrants. Only the warrants had a known market value. The sum of the fair val
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Answer: discount on bonds payable

Explanation:

Based on the information given, since the sum of the fair value of the warrants and the face amount of the bonds exceeds the cash proceeds, then the excess will be reported as the discount on bonds payable.

The discount on the bonds payable occurs in a scenario whereby the bonds are issued for a lesser amount than their face or their maturity amount.

The reason for this is when the bonds have a stated interest rate that is smaller than market interest rate for similar bonds.

6 0
3 years ago
Saar Associates sells two licenses to Kim &amp; Company on September 1, 2021. First, in exchange for $100,000, Saar provides Kim
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$110,000 revenue will Saar recognise in 2021 under this arrangement

Solution:

First, in exchange for $100,000

Second, in exchange for $90,000

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6 0
3 years ago
The Centers for Disease Control and Prevention (CDC) defines a healthy sleep duration
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a. The point estimate of the married people that sleep well is = 0.6299. The confidence interval for the mean hours of sleep for those that have never been married but report good sleep is 0.6186, 0.6412

b. The point estimate of the number of hours for people that have never been married = 7.2257

95% confidence interval for the mean number of  hours of sleep for those who have never been married = 7.2065, 7.2447

c. the estimated number of sleep for those that have never been married = 7.729 hours

a. The point estimate

P=\frac{Xp}{n}

Xp = successes\\n = sample size\\

Those who have never been married n = 7044

Xp = those who sleep for 7 hours at least

To get Xp, the <u>excel function </u>

Countif(range, criteria)

Countif(A:A, >=7)

This gives Xp = 4437

Point estimate =

\frac{4477}{7044}

= 0.6299

The point estimate of the married people that sleep well is = 0.6299

At 95% interval of confidence,

α = 1-0.95 = 0.05

α/2 = 0.05/2 = 0.025

Z0.025 = 1.96 ( Use the standard probability normal table)

Margin of Error

=M.E = 1.96\sqrt \frac{0.6299(1-0.6299)}{7044} \\\\= 1.96\sqrt{0.000033} \\\\1.96*0.0057

= 0.0113

The 95% confidence interval

= 0.6299 - 0.0113 , 0.6299 + 0.0113

= 0.6186, 0.6412

The confidence interval for the mean hours of sleep for those that have never been married is 0.6186, 0.6412

b. Sample mean

x = ∑x/n

x = number of sleep of the never been married

Mean is calculated using excel function

Average(range)

Average(a:a)

This gives the sample mean = 7.2257

The point estimate of the number of hours for people that have never been married = 7.2257

<u>Standard deviation</u> using excel =

Stdev(A:A) = 0.8211

Margin of error =1.96*\frac{0.8211}{\sqrt{7044} }

= 0.0192

The<u> confidence interval</u> =

= 7.2257-0.0192, 7.2257+0.0192

= 7.2065, 7.2447

95% confidence interval for the mean number of  hours of sleep for those who have never been married = 7.2065, 7.2447

c. From the available data, the mean number of sleep per day that is gotten from the 4437 people that are unmarried and sleep healthily for at least 7 hours = 34295.1

Mean = 34295.1/4437

= 7.729

the estimated number of sleep for those that have never been married = 7.729 hours

Read more on brainly.com/question/15601189?referrer=searchResults

6 0
3 years ago
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