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DaniilM [7]
3 years ago
12

Which of the following equations are equivalent? Check all that apply.

Mathematics
2 answers:
Verdich [7]3 years ago
5 0
 the answer is A. and B. 
Gemiola [76]3 years ago
5 0
Hi there!
We are basically asked to solve each equation for x. Here...
A. 
2 + x = 5
-2        -2
x = 3
B.
x + 1 = 4
x = 3
C.
9 + x = 6
x = -3
D.
x + (-4) = 7
x - 4 = 7
x = 11
E.
-5 + x = -2
x = 3
The answer is that equations A, B, and E are equivalent. Hope this helps and have a great day!

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a leaf hangs from a branch 12 feet in the air. it falls to the ground at a rate of 0.25 feet per second. which graph could repre
Kipish [7]
For this case we have an equation of the form:
 h (t) = (1/2) * (a) * (t ^ 2) + v0 * t + h0

 Where,
 h0: initial height
 v0: initial speed
 a: acceleration
 Substituting values we have:
 h (t) = (1/2) * (- 32) * (t ^ 2) + 0.25 * t + 12

 Rewriting we have:
 h (t) = -16t ^ 2 + 0.25 * t + 12

 Note: see attached image
 Answer:
 
h (t) = -16t ^ 2 + 0.25 * t + 12

7 0
3 years ago
james is stocking shelves with notebooks. if he has 5 different notebooks, in how many ways can he arrange them on a shelf?
nadya68 [22]

Answer: 120

Step-by-step explanation: I got it right, hope this helps ✨

6 0
3 years ago
Read 2 more answers
Sausages come in packets of 5 Bread rolls come in packets of 4 Colin wants to buy enough
tino4ka555 [31]

Answer:

The minimum packs of sausages that he needs is 1 and he needs 2 packs of rolls

Step-by-step explanation:

1 pack of sausages contains 5 sausages and 1 pack of rolls contains 4 rolls. Collin needs the same number of sausages and rolls. He needs 2 packs of bread rolls because 4 x 2 is 8 which means there is enough

hope this helps

5 0
3 years ago
Erica sells magazine subscriptions and makes a flat rate of $5.35 for each subscription see cells if Erica man $42.80 on Monday
Kay [80]
Erica would have sold 121 subscriptions in 3 days.
4 0
4 years ago
Read 2 more answers
How many integers between 10000 and 99999, inclusive, are divisible by 3 or<br> 5 or 7?
Yuki888 [10]

Answer: Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

Step-by-step explanation:

Since we have given that

Integers between 10000 and 99999 = 99999-10000+1=90000

n( divisible by 3) = \dfrac{90000}{3}=30000

n( divisible by 5) = \dfrac{90000}{5}=18000

n( divisible by 7) = \dfrac{90000}{7}=12857.14

n( divisible by 3 and 5) = n(3∩5)=\dfrac{90000}{15}=6000

n( divisible by 5 and 7) = n(5∩7) = \dfrac{90000}{35}=2571.42

n( divisible by 3 and 7) = n(3∩7) = \dfrac{90000}{21}=4285.71

n( divisible by 3,5 and 7) = n(3∩5∩7) = \dfrac{90000}{105}=857.14

As we know the formula,

n(3∪5∪7)=n(3)+n(5)+n(7)-n(3∩5)-n(5∩7)-n(3∩7)+n(3∩5∩7)

=30000+18000+12857.14-6000-2571.42-4258.71+857.14\\\\=48884.15

Hence, there are approximately 48884 integers are divisible by 3 or 5 or 7.

5 0
4 years ago
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