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natima [27]
2 years ago
15

Give me the full working and I give you stars ​

Mathematics
2 answers:
pishuonlain [190]2 years ago
6 0

Answer:

1071 m²

Step-by-step explanation:

The area of a rectangle is basically the length multiplied with the width. The <u>length</u> can be any side length, but the <u>width</u> must be the <u>adjacent</u> to the <u>length.</u> Thus, we can let the <u>length</u> be 63 meters and the <u>width</u> be 17 meters as the <u>width</u> is adjacent to the <u>length.</u>

⇒ Area of rectangle = Width × Length

⇒ Area of rectangle = 17 × 63

⇒ Area of rectangle = 1071 m²

kari74 [83]2 years ago
4 0

→ Area of rectangle = Length * Width

Here given:

  • Length = 63 m
  • Width = 17 m

Here area:

  • L * W
  • 63 * 17
  • 1071 m²
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babunello [35]
A+b = 5
b+c= 3 1/2
2 times 2 + 3 = 7
a times d =8
c+c = 1
(e)2 = 1/9
8 0
3 years ago
Read 2 more answers
Its on the picture, plz go fast
Naily [24]

Answer:

Elimination

Step-by-step explanation:

You would not do substitution since it would not work so you do elimination since the 4y and -4y eliminate then you just solve for it.

7 0
2 years ago
Exhibit B: A restaurant has tracked the number of meals served at lunch over the last four weeks. The data shows little in terms
Mekhanik [1.2K]

Answer:

Option E is correct.

The expected number of meals expected to be served on Wednesday in week 5 = 74.2

Step-by-step Explanation:

We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.

Week

Day 1 2 3 4 | Total

Sunday 40 35 39 43 | 157

Monday 54 55 51 59 | 219

Tuesday 61 60 65 64 | 250

Wednesday 72 77 78 69 | 296

Thursday 89 80 81 79 | 329

Friday 91 90 99 95 | 375

Saturday 80 82 81 83 | 326

Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952

Total number of meals served at lunch on Wednesdays over the 4 weeks = 296

Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443

Total number of meals expected to be served in week 5 = 490

Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3

Checking the options,

74.3 ≈ 74.2

Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2

Hope this Helps!!!

8 0
2 years ago
Point N is on line segment MO. Given NO=2x−3, MO=3x+5, and MN=2x+3, determine the numerical length of MO.
ELEN [110]

Answer:-19

Step-by-step explanation:

3x+5-(2x-3)=0

3x+5-2x+3=0

x+8=0

x=-8

substitute x into 3x+5 to find the length of MO

3x+5

3(-8)+5

-24+5

-19

6 0
3 years ago
Please explain it step by step I dont get it.
Ivenika [448]
So, we’re looking for the amount of money Tom needs to spend to get his free meal.
X + 30.25 >
X > 9.75

X is the additional amount that Tom needs to spend. You subtract 30.25 on both sides in order to solve for x.

So, your answer would be at least $19.75
5 0
2 years ago
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