All categories

2 years ago

(5, 4.07, 5.26, 4.3, 5.02) 5.02 < ?

Mathematics

1 answer:

aleksandr82 [10.1K]2 years ago

8 0

Answer:

5.26

Step-by-step explanation:

Of the numbers given, opnly 5.26 is larger than 5.02.

You might be interested in

Let A= {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}. Suppose an element of A is randomly selected. What is the probability that it belongs to

gregori [183]

<h3>Answer: 3/5</h3>

============================================================

Explanation:

The set {1, 2}U{2, 6, 7, 9}U{5, 6, 7} simplifies to {1,2,5,6,7,9} after we combine everything and sort the values. We toss any duplicates.

Let B = {1,2,5,6,7,9}

There are 6 items in set B out of 10 items in set A.

The probability of landing in set B, if you pick something randomly from A, is 6/10 = 3/5

8 0

2 years ago

Read 2 more answers

Can someone plz help me answer this i will give brainliest due by 12:30

julsineya [31]

Answer: Yes

Step-by-step explanation:

I'm pretty sure it's correct so yes

6 0

2 years ago

Which two operations are needed to write the expression that represents "five less than the quotient of a number anc

tatiyna

Division and subtraction

8 0

2 years ago

Read 2 more answers

A certain semiconductor device requires a tunneling probability of T = 10-5 for an electron tunneling through a rectangular barr

Goryan [66]

Answer:

Generally the barrier width is $a = 1.9322 *10^{-9} \ m$

Step-by-step explanation:

From the question we are told that

The tunneling probability required is $T = 1 * 10^{-5}$

The barrier height is $V_o = 0.4 eV$

The electron energy is $E = 0.08eV$

Generally the wave number is mathematically represented as

$k = \sqrt{ \frac{2 * m [V_o - E]}{\= h^2} }$

Here m is the mass of the electron with the value $m = 9.11 *10^{-31} \ kg$

h is is know as h-bar and the value is $\= h = 1.054*10^{-34} \ J \cdot s$

$k = \sqrt{ \frac{2 * 9.11 *10^{-31 } [0.4 - 0.04] * 1.6*10^{-19}}{[1.054*10^{-34}^2]} }$

=> $k = 3.073582 *10^{9} \ m^{-1}$

Generally the tunneling probability is mathematically represented as

$T = 16 * \frac{E}{V_o } * [1 - \frac{E}{V_o} ] * e^{-2 * k * a}$

$1.0 *10^{-5} = 16 * \frac{0.04}{0.4 } * [1 - \frac{0.04}{0.4} ] * e^{-2 * 3.0736 *10^{9} * a}$

=> $6.944*10^{-6}= e^{-2 * 3.0736 *10^{9} * a}$

Taking natural log of both sides

$ln[6.944*10^{-6}] = -2 * 3.0736 *10^{9} * a}$

=> $-11.8776 = -2 * 3.0736 *10^{9} * a}$

=> $a = 1.9322 *10^{-9} \ m$

4 0

2 years ago

The door to my classroom is 84 inches tall. How many blocks would I need to stack to the height of the door, If each block is 2

nata0808 [166]

Answer:

42 blocks

Step-by-step explanation:

If each block is 2 inches, and the height of the door is 84 inches, you need to divide the height by the block size. Once you divide 84 by 2, you should get 42 blocks as your answer.

4 0

2 years ago

(5, 4.07, 5.26, 4.3, 5.02) 5.02 < ?​

(5, 4.07, 5.26, 4.3, 5.02) 5.02 < ?