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kirill115 [55]
2 years ago
10

♥|| Please help me A.S.A.P i will make you brainliest!||♥

Mathematics
2 answers:
dmitriy555 [2]2 years ago
5 0
63 + a = 90; subtract 63 from both sides of the equation.
Taya2010 [7]2 years ago
4 0

Answer:

Option B, 63 + a = 90; subtract 63 from both sides of the equation

Step-by-step explanation:

When the sum of two angles is equal to 90 degrees, they are called complementary angles.

Here, we  know the one angle measure is 63°

Let's consider unknown angle as a.

63 °+ a = 90°

63 °+ a -63° = 90° - 63° ( subtract 63 from both sides of the equation)

a = 90° - 63°

a = 27°

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Which two operations are needed to write the expression that represents "eight more than the product of a number and two"?
sp2606 [1]

For this case we must represent the following expression algebraically:

"eight more than the product of a number and two"

Let "x" be the variable that represents the unknown number

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the product of a number and two is represented as: 2x

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Find an equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)
sattari [20]

Answer:

(x+5)^{2}=-4(y+3)

Step-by-step explanation:

Given:

Focus point = (-5, -4)

Vertex point = (-5, -3)

We need to find the equation for the parabola.

Solution:

Since the x-coordinates of the vertex and focus are the same,

so this is a regular vertical parabola, where the x part is squared. Since the vertex is above the focus, this is a right-side down parabola and p is negative.

The vertex of this parabola is at (h, k) and the focus is at (h, k + p). So, directrix is y = k - p.

Substitute y = -4 and k = -3.

-4 = -3+p

p=-4+3

p=-1

So the standard form of the parabola is written as.

(x-h)^{2}=4p(y-k)

Substitute vertex (h, k) = (-5, -3) and p = -1 in the above standard form of the parabola.

So the standard form of the parabola is written as.

(x-(-5))^{2}=4(-1)(y-(-3))

(x+5)^{2}=-4(y+3)

Therefore, equation for the parabola with focus at (-5,-4) and vertex at (-5,-3)

(x+5)^{2}=-4(y+3)

7 0
3 years ago
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