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3 years ago

Determine whether the equation has no solution, one solution, or infinitely many solutions. 7(12 – 2 x ) = 4(3 – 3 x )

Mathematics

1 answer:

Alex777 [14]3 years ago

3 0

Answer: The equation has one solution

Step-by-step explanation: First , open the brackets

7( 12 - 2x ) = 4 (3 - 3x )

84 - 14x = 12 - 12x

collect the like terms

84 - 12 = - 12x + 14x

72 = 2x

Therefore divide through by 2

x = 72/2

x = 36

Therefore, the equation has only one solution

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The basketball coach at a small local college believes that his team plays better and scores more points in front of larger crow

Orlov [11]

Answer:

Step-by-step explanation:

Given that points scored is the dependent variable Y and Number of people attending the game is the independent variable is independent variable x

The correlation coefficient, slope and intercept are calculated as shown below:

x y

378 54

350 57

320 59

478 80

451 82

250 75

489 73

451 53

410 67

215 78

113 67

250 56

450 85

489 101

472 99

Mean 371.0666667 72.4

std dev 117.5138087 15.42632259

covariance 667.5733333

r 0.394558035

Slope 3.005642934

Intercept 153.4581182

y = 3.006x+153.46 is the regression line.

Corre = 0.3945 (weak positive)

8 0

3 years ago

Help please I am confused?

ELEN [110]

Answer:

Given m∠RST = (15x - 10)o

Using angle addition postulate:

m∠RST = m∠RSP + m∠PST (15x - 10)= (x + 25)+ (5x + 10)(15x - 10)=

so your answer would be (6x+35)

Step-by-step explanation:

4 0

3 years ago

Convert 3 18/25 to a decimal using long division.

zaharov [31]

Change into improper fraction
take 3 x 25+18 divided by 25=93\25
93\25=3.72

3 0

3 years ago

A marine aquarium has a small tank and a large tank, each containing only red and blue fish. In each tank, the ratio of red fish

Anna007 [38]

Answer:

Ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

Step-by-step explanation:

Let the number of red fish and blue fish in the large tank are x and y respectively.

Similarly ratio of red fish and blue fish in the small tank are x' and y' respectively.

Since in each tank ratio of the red fish to blue fish is 333 : 444

That means x : y = 333 : 444

Or $\frac{x}{y}=\frac{333}{444}$

⇒ $\frac{x}{y}=\frac{3}{4}$

⇒ y = $\frac{4x}{3}$ --------(1)

Similarly x' : y' = 333 : 444

⇒ $\frac{x'}{y'}=\frac{333}{444}$

⇒ $\frac{x'}{y'}=\frac{3}{4}$

⇒ x' = $\frac{3y'}{4}$ ------(2)

Ratio of the fish in large tank to the fish in small tank is 464646 : 555

So (x + y) : (x' + y') = 464646 : 555

$\frac{x+y}{x'+y'}=\frac{464646}{555}$

Now we replace the values of x and y' from equation (1) and equation (2)

$\frac{(x+\frac{4x}{3})}{(\frac{3y'}{4}+y')}=\frac{464646}{555}$

$\frac{\frac{7x}{3}}{\frac{7y'}{4}}=\frac{464646}{555}$

$\frac{4}{3}\times \frac{x}{y'}=\frac{464646}{555}$

$\frac{x}{y'}=\frac{3}{4}\times \frac{464646}{555}$

$\frac{x}{y'}=\frac{232323}{370}$

$\frac{y'}{x}=\frac{370}{232323}$

$\frac{y'}{x}=\frac{10}{6279}$

Therefore, ratio of blue fish in the small tank to the red fish in large tank is 10 : 6279

4 0

4 years ago

Which statements are true from the graph ? Check all that apply:

Flura [38]

The statements that are true from the graph are:

The line is horizontal
The line goes through (4, 4 )
The y- values are all 4

<h3>Calculations and Parameters</h3>

Given the graph, we can note some things:

There is a line with a slope of zero.
This is a horizontal line parallel to the x-axis.
The equation of the line is y = c

c is the value of the y- coordinates the line passes through.

The line passes through (0, 4 ) with a y- coordinate of 4

Therefore, the equation of the line of y= 4