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2 years ago

find the area of a regular pentagon inscribed in a circle whose equation is given by (x-4)^2 + (y+2)^2=25

1 answer:

7 0

The radius is √25=5 in this case.
find the area of each triangles first. (the pentagon can be divided into 5 isosceles triangles)
the two equal sides are 5 each, the angle between them is 360/5=72 degree, so the base side is 2*5*sin36, and the height is 5*Cos36
the area of each triangle is (1/2)*2*5*Sin36*5*Cos36
the total area of the 5 triangles is: 5*(1/2)*2*5*Sin36*5*Cos36
use a calculator: A≈59.44

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Is this true or no plz help

il63 [147K]

Im pretty sure its No.

7 0

3 years ago

An aircraft factory manufactures airplane engines. The unit cost C (the cost in dollars to make each airplane engine) depends on

butalik [34]

Answer:

90 engines must be made to minimize the unit cost.

Step-by-step explanation:

Vertex of a quadratic function:

Suppose we have a quadratic function in the following format:

$f(x) = ax^{2} + bx + c$

It's vertex is the point $(x_{v}, y_{v})$

In which

$x_{v} = -\frac{b}{2a}$

$y_{v} = -\frac{\Delta}{4a}$

Where

$\Delta = b^2-4ac$

If a>0, the minimum value of the function will happen for $x = x_v$

C(x)=x²-180x+20,482

This means that $a = 1, b = -180, c = 20482$

How many engines must be made to minimize the unit cost?

x value of the vertex. So

$x_{v} = -\frac{b}{2a} = -\frac{-180}{2(1)} = 90$

90 engines must be made to minimize the unit cost.

3 0

2 years ago

A farm has a small water tank with a diameter of 10 feet and a height of 4 feet. What is the lateral surface area of the water t

svp [43]

The Shape in this question is a cylinder
And the formula for finding the L.S.A of a cylinder is 2*pie*r*h
From the question, we are given the diameter so to get the radius we will divide the value for diameter by 2
D = 10/2
=5
Now, 2*3.14*5*4
L.S.A =125.6

5 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST PLEASE HELP

Serga [27]

It’s the second one, 65.4

V=1
6πd3=1
6·π·53≈ 65.44985in³

7 0

3 years ago

From a group of 3 men and 4 women, a delegation of 2 is selected. What is the expected number of men in the delegation?

Ostrovityanka [42]

Answer:

The expected number of men in the delegation is 0.86.