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Harlamova29_29 [7]
3 years ago
11

find the area of a regular pentagon inscribed in a circle whose equation is given by (x-4)^2 + (y+2)^2=25

Mathematics
1 answer:
makkiz [27]3 years ago
7 0
The radius is √25=5 in this case.
find the area of each triangles first. (the pentagon can be divided into 5 isosceles triangles)
the two equal sides are 5 each, the angle between them is 360/5=72 degree, so the base side is 2*5*sin36, and the height is 5*Cos36
the area of each triangle is (1/2)*2*5*Sin36*5*Cos36
the total area of the 5 triangles is: 5*(1/2)*2*5*Sin36*5*Cos36
use a calculator: A≈59.44

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Give the values of a, b, and c needed to write the equation's general form.<br>1/4x^2+5=0
Firdavs [7]

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   Hi my lil bunny!

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Let's solve your equation step-by-step.

\frac{1}{4} x^2+5=0

For this equation: a=0.25, b=0, c=5

0.25x^2 + 0x + 5 = 0

Step 1: Use quadratic formula with a=0.25, b=0, c=5.

x = \frac{-b ± \sqrt{b^2 - 4ac} }{2a}

x = \frac{-(0) ± \sqrt{(0)^2 -4 (0.25) (5)  } }{2(0.25)}

x = \frac{0 ± \sqrt{-5} }{0.5}

Answer : No Real Solutions.

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If this helped you, could you maybe give brainliest..?

Also Have a great day/night!

❀*May*❀

5 0
3 years ago
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