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3 years ago

Help ASAP with this questions.

Mathematics

1 answer:

Finger [1]3 years ago

4 0

A= h (a+b)

solving for b:

Solve for b, i.e separate b in one side and the other terms in the other side

A = ah + bh

A - ah = bh

(A - ah) / h = b

$b= \frac{A-ah}{h}$

I hope that helps!

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Help me with this if anyone can! Please and thank you

Valentin [98]

ANSWER

$y = 3x - 3$

EXPLANATION

Let

$y = mx + c$

be the equation.

We can choose any two ordered pairs to determine the equation of the relation.

$(6,15) \: and \: (8,21)$

We find m using the formula;

$m = \frac{y_2-y_1}{x_2-x_1}$

$m = \frac{21 - 15}{8 - 6} = \frac{6}{2} = 3$

The equation becomes

$y = 3x + c$

When x=6, y=15.

This implies that,

$15 = 3(6) + c$

$15= 18 + c$

$15 - 18= c$

$c = -3$

The equation of the relation is therefore,

$y = 3x -3$

3 0

4 years ago

The profile of the cables on a suspension bridge may be modeled by a parabola. The central span of the bridge is 1210 m long and

brilliants [131]

Answer:

The approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

Step-by-step explanation:

The equation of the parabola is:

$y=0.00035x^{2}$

Compute the first order derivative of y as follows:

$y=0.00035x^{2}$

$\frac{\text{d}y}{\text{dx}}=\frac{\text{d}}{\text{dx}}[0.00035x^{2}]$

$=2\cdot 0.00035x\\\\=0.0007x$

Now, it is provided that |x | ≤ 605.

⇒ -605 ≤ x ≤ 605

Compute the arc length as follows:

$\text{Arc Length}=\int\limits^{x}_{-x} {1+(\frac{\text{dy}}{\text{dx}})^{2}} \, dx$

$=\int\limits^{605}_{-605} {\sqrt{1+(0.0007x)^{2}}} \, dx \\\\={\displaystyle\int\limits^{605}_{-605}}\sqrt{\dfrac{49x^2}{100000000}+1}\,\mathrm{d}x\\\\={\dfrac{1}{10000}}}{\displaystyle\int\limits^{605}_{-605}}\sqrt{49x^2+100000000}\,\mathrm{d}x\\\\$

Now, let

$x=\dfrac{10000\tan\left(u\right)}{7}\\\\\Rightarrow u=\arctan\left(\dfrac{7x}{10000}\right)\\\\\Rightarrow \mathrm{d}x=\dfrac{10000\sec^2\left(u\right)}{7}\,\mathrm{d}u$

$\int dx={\displaystyle\int\limits}\dfrac{10000\sec^2\left(u\right)\sqrt{100000000\tan^2\left(u\right)+100000000}}{7}\,\mathrm{d}u$

$={\dfrac{100000000}{7}}}{\displaystyle\int}\sec^3\left(u\right)\,\mathrm{d}u\\\\=\dfrac{50000000\ln\left(\tan\left(u\right)+\sec\left(u\right)\right)}{7}+\dfrac{50000000\sec\left(u\right)\tan\left(u\right)}{7}\\\\=\dfrac{50000000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+5000x\sqrt{\dfrac{49x^2}{100000000}+1}$

Plug in the solved integrals in Arc Length and solve as follows:

$\text{Arc Length}=\dfrac{5000\ln\left(\sqrt{\frac{49x^2}{100000000}+1}+\frac{7x}{10000}\right)}{7}+\dfrac{x\sqrt{\frac{49x^2}{100000000}+1}}{2}|_{limits^{605}_{-605}}\\\\$

$=1245.253707795227\\\\\approx 1245.25$

Thus, the approximated length of the cables that stretch between the tops of the two towers is 1245.25 meters.

7 0

3 years ago

Which expressions are correct for the situation?

Ludmilka [50]

One of the Answers is C.

8 0

4 years ago

Read 2 more answers

For what value of x is the rational expression below undefined?

Blizzard [7]

Answer: The expression is undefined for x=4 and x=5.

The expression is undefined for any x that makes the denominator 0. This leads to solving a quadratic equation:

$\frac{x+3}{x^2-9x+20}\\x^2-9x+20\neq 0\\x_{1,2}\neq\frac{9\pm\sqrt{9^2-80}}{2}=\frac{9\pm1}{2}\\x_1\neq4\\x_2\neq5$

4 0

3 years ago

Read 2 more answers

Please help. i need to pass.

FrozenT [24]

Plug 8 for y

8 = 2x + 4

Subtract 4

4 = 2x

Divide by 2

x = 2

Plug 16 for y

16 = 2x + 4

Subtract by 4

12 = 2x

Divide by 2

x = 6

Substitute 20 for y

20 = 2x + 4

16 = 2x

x = 8

Substitute 22 for y

22 = 2x + 4

18 = 2x

9 = x

So the values are 2, 6, 8, 9

5 0

4 years ago