Answer:
20 ton
Step-by-step explanation:
We created a system of two separate equations to answer these questions.
"y" will be the total cost to transport the sugar
"x" will be the amount of sugar transported
Therefore, we have to:
y = 3995 + 225.50 * x
y = 6500 + 100.25 * x
We must establish these equations equal to each other because it asks how much of x is necessary to make the same amount of y, therefore:
3995 + 225.50 * x = 6500 + 100.25 * x
solved we have:
225.50 * x - 100.25 * x = 6500 - 3995
125.25 * x = 2505
x = 2505 / 125.25
x = 20
which means that when the amount of sugar transported is 20 tons, the price is the same
<span>The solution:
= 40, p = q = 0.5
P[x] = nCx *p^x *q^(n-x)
when p = q = 0.5, the formula simplifies to
P[x] = nCx/2^n = 40Cx/2^40
at least 18 of each type means 18 to 22 of (say) type I
P(18 <= X <= 22) = 0.5704095 <-------
qb
mean = 40*0.5 = 20
SD = sqrt(npq) = sqrt(40*0.5*0.5) = 3.1623
z1= (18-20)/3.1623 = -0.63 , z2 = (22-20)/3.1623 = 0.63
P(-0.63 < z < 0.63) = 0.4713 <-------</span>
The answer to your problem is A due to the slope of your line being -1/3x.
You can find this slope by picking two points on your graph [i.e. (-1,3) and (0,0)].
Find the difference between the two points, which is a one for the x value and a three for the y values. Now you have a slope of 1/3.
But wait! The slope is downwards, therefore a negative must be applied to your slope.
This provides you with a slope of -1/3x, therefore:
y = -1/3x
Answer:
58.0
Step-by-step explanation:
Given the data:
56 65 62 53 68 58 65 52 56
Reorderd data: 52, 53, 56, 56, 58, 62, 65, 65, 68
Median = 1/2(n + 1) th term
n = sample size = 9
Hence,
Median = 1/2(9 + 1)th term
Median = 1/2(10)th term
Median = 5th term
5th term in the reordered data = 58
Hence, median age is 58
