Write a conjecture that describes the pattern in each sequence. Then use your conjecture to find the next item in the sequence.

The double number line shows that in 222 minutes, Pogo the dog can fetch a frisbee 666 times. Based on the ratio shown in the do

Ilia_Sergeevich [38]

Answer:

Dog Pogo will fetch the frisbee 12 times in 4 minutes.

Step-by-step explanation:

Given:

Number of minutes required =2 minutes.

Number of times frisbee fetch by dog = 6 times

We need to find Number of times the dog can fetch the frisbee in 4 minutes.

First we will find number of frisbee fetch in minute.

In 2 minutes = 6 times frisbee fetched by the dog

so in 1 minute = Number of times frisbee fetched by the dog in 1 minute.

By using Using Unitary method we get;

Number of times frisbee fetched by the dog in 1 minute = $\frac{6}{2} =3$

Hence in 1 minutes the dog can fetch frisbee 3 times.

for 1 min = 3 times frisbee is been fetched by dog

So for 4 minutes = Number of times frisbee is been fetched by dog in 4 min.

Again by using Unitary Method we get;

Number of times frisbee is been fetched by dog in 4 min = $3\times4 = 12$

Hence Dog Pogo will fetch the frisbee 12 times in 4 minutes.

8 0

3 years ago

Read 2 more answers

Simplify (2√5+3√7)^2.

Irina18 [472]

\[(2\sqrt{5}+3\sqrt{7})(2\sqrt{5}+3\sqrt{7})\]

3 0

3 years ago

Read 2 more answers

Wish someone can do this for me.

Makovka662 [10]

Given : Two inequality is given to us . The inequality is v + 8 ≤ -4 and v - 6 ≥ 10 .

To Find : To write those two inequality as a compound inequality with integers .

Solution: First inequality given to us is v + 8 ≤ -4 . So let's simplify it ;

⇒ v + 8 ≤ -4 .

⇒ v ≤ -4 - 8.

⇒ v ≤ -12 .

Now , on simplifying the second inequality ,

⇒ v - 6 ≥ 10 .

⇒ v ≥ 10 + 6.

⇒ v ≥ 16 .

Hence the required answer will be :

$\Large{\boxed{\red{\bf \blue{\dag} v\leqslant -12 \:\:or\:\:v\geqslant 16}}}$

First one implies that v is less than or equal to -12 whereas the second one implies that v is greater than or equal to 16 .

5 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. If an answer does not exist, enter DNE

Furkat [3]

Answer:

x = -6 and x = 4

Step-by-step explanation:

In math, the critical points of a function are the points where the derivative equals zero.

So, first we will find the derivative of the function. The derivative is:

$f'(x)=3x^2 +6x-72$

Now, we are going to make the derivative equal zero and find the answers of the equation.

$3x^2 +6x-72=0\\3(x^2 +2x-24)=0\\3(x+6)(x-4)=0\\$

So we have that the critical points are the answers to this equation:

$x+6= 0 \\x= - 6$

and

$x-4=0\\x=4$

Thus, the critical points are x=-6 and x=4

8 0

3 years ago

Determine the number and types of solutions for 6m^2-3m-4=0

Anna11 [10]

Answer:

2 real solutions

Step-by-step explanation:

Remember this messy thing?

$x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

The quadratic formula, as it's called, gives us the roots to any quadratic equation in standard form (ax² + bx + c = 0). The information on the type of roots is contained entirely in that bit under the square root symbol (b² - 4ac), called the discriminant. If it's non-negative, we'll have real roots, if it's negative, we'll have complex roots.

For our equation, we have a discrimant of (-3)² - 4(6)(-4) = 9 + 96 = 105, which is non-negative, so we'll have real solutions, and since quadratics are degree 2, we'll have exactly 2 real solutions.

4 0

3 years ago