Answer:
it would be c because it is plotted correctly
Answer:
4x - 20
Step-by-step explanation:
Combine like terms (those with the same amount of variables:
x + x + x + x = 4x
4x - 20 => Note: You cannot combine these two terms, because they do not have the same amount of variables (one having one variable (x), the other being a constant (no variable) ).
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Answer:
okay I don't have to work at rito pag nasagutan the gathered from the story is about
Short Answer: 6 + (44 + 28)
Long Answer:
Change the parentheses to include 28 and not include 6. According the the property, changing the parentheses this way does not affect the sum. In other words, changing the order of addition does not change your answer.
Answer:
Roots are not real
Step-by-step explanation:
To prove : The roots of x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0 are real for all real values of k ?
Solution :
The roots are real when discriminant is greater than equal to zero.
i.e. b^2-4ac\geq 0b
2
−4ac≥0
The quadratic equation x^2 +(1-k)x+k-3=0x
2
+(1−k)x+k−3=0
Here, a=1, b=1-k and c=k-3
Substitute the values,
We find the discriminant,
D=(1-k)^2-4(1)(k-3)D=(1−k)
2
−4(1)(k−3)
D=1+k^2-2k-4k+12D=1+k
2
−2k−4k+12
D=k^2-6k+13D=k
2
−6k+13
D=(k-(3+2i))(k+(3+2i))D=(k−(3+2i))(k+(3+2i))
For roots to be real, D ≥ 0
But the roots are imaginary therefore the roots of the given equation are not real for any value of k.
