Question

" alt="A=\frac{1}{2}\pi w^2+2lw" align="absmiddle" class="latex-formula">

Solve for L

Answer 1

Answer:

l = a/(2 w) - (π w)/4

Step-by-step explanation:

Solve for l:

a = 2 l w + (π w^2)/2

a = 2 l w + (π w^2)/2 is equivalent to 2 l w + (π w^2)/2 = a:

2 l w + (π w^2)/2 = a

Subtract (π w^2)/2 from both sides:

2 l w = a - (π w^2)/2

Divide both sides by 2 w:

Answer: l = a/(2 w) - (π w)/4

Answer 2

Answer:

$l=\dfrac{2A-\pi w^2}{4w}$

Step-by-step explanation:

Subtract terms not containing L, then divide by its coefficient.

$A=\frac{1}{2}\pi w^2+2lw\\\\A-\frac{1}{2}\pi w^2=2lw\\\\l=\dfrac{2A-\pi w^2}{4w}$