Add.<br> (5n^2+4n)+(3n^2+6n)

What is the x and y intercept for 4x-5y=-20

yuradex [85]

X intercept is when y = 0 so 4x = -20, x=-5
y intercept when x = 0 so -5y = -20, y=4

7 0

3 years ago

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How does the multiplicity of a zero determine the behavior of the graph at that zero?

grin007 [14]

If the graph crosses the x-axis and appears almost linear at the intercept, it is a single zero. If the graph touches the x-axis and bounces off of the axis, it is a zero with even multiplicity. If the graph crosses the x-axis at a zero, it is a zero with odd multiplicity. The sum of the multiplicities is the degree

8 0

2 years ago

Find the curl of ~V<br> ~V<br> = sin(x) cos(y) tan(z) i + x^2y^2z^2 j + x^4y^4z^4 k

ch4aika [34]

Given

$\vec v = f(x,y,z)\,\vec\imath+g(x,y,z)\,\vec\jmath+h(x,y,z)\,\vec k \\\\ \vec v = \sin(x)\cos(y)\tan(z)\,\vec\imath + x^2y^2z^2\,\vec\jmath+x^4y^4z^4\,\vec k$

the curl of $\vec v$ is

$\displaystyle \nabla\times\vec v = \left(\frac{\partial h}{\partial y}-\frac{\partial g}{\partial z}\right)\,\vec\imath - \left(\frac{\partial h}{\partial x}-\frac{\partial f}{\partial z}\right)\,\vec\jmath + \left(\frac{\partial g}{\partial x}-\frac{\partial f}{\partial y}\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ - \left(4x^3y^4z^4-\sin(x)\cos(y)\sec^2(z)\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

$\nabla\times\vec v = \left(4x^4y^3z^4-2x^2y^2z\right)\,\vec\imath \\\\ + \left(\sin(x)\cos(y)\sec^2(z)-4x^3y^4z^4\right)\,\vec\jmath \\\\ + \left(2xy^2z^2+\sin(x)\sin(y)\tan(z)\right)\,\vec k$

7 0

2 years ago

B. Why does using FOIL on polynomial expressions match so closely to integer

Anastasy [175]

FOIL is a mnemonic rule for multiplying binomial (that is, two-term) algebraic expressions.
FOIL abbreviates the sequence "First, Outside, Inside, Last"; it's a way of remembering that the product is the sum of the products of those four combinations of terms.

For instance, if we multiply the two expressions
(x + 1) (x + 2)
then the result is the sum of these four products:
x times x (the First terms of each expression)
x times 2 (the Outside pair of terms)
1 times x (the Inside pair of terms)
1 times 2 (the Last terms of each expression)
and so
(x + 1) (x + 2) = x^2 + 2x + 1x + 2 = x^2 + 3x + 2
[where the ^ is the usual way we indicate exponents here in Answers, because they're hard to represent in an online text environment].

Now, compare this to multiplying a pair of two-digit integers:
37 × 43
= (30 × 40) + (30 × 3) + (7 × 40) + (7 × 3)
= 1200 + 90 + 280 + 21
= 1591

The reason the two processes resemble each other is that multiplication is multiplication; the difference in the ways we represent the factors doesn't make it a fundamentally different operation.

7 0

2 years ago

Find the simple interest of 600 Naira for 1 whole number 1 over 2 years at 3 whole 1 over 6 % per annum

Butoxors [25]

Answer:

₦28.5

Step-by-step explanation:

$interest = \frac{600 \times 1.5 \times 3 \frac{1}{6} }{100}$

7 0

2 years ago

Add. (5n^2+4n)+(3n^2+6n)