All categories

4 years ago

What is the value of 20 + 3(7+4) + 5 +2(7+9)

2 answers:

6 0

Follow the order of operations.

First do what is inside the parenthesis

20 + 3(7+4) + 5 + 2(7+9)
20 + 3(11) + 5 + 2(16)

Next, do the multiplication

20 + 3(11) + 5 + 2(16)
20 + 33 + 5 + 32

Then add

20 + 33 + 5 + 32 = 90

aleksandrvk [35]4 years ago

4 0

The answer is 90 use order of operations

You might be interested in

What are the endpoint coordinates for the midsegment of △PQR that is parallel to PQ¯¯¯¯¯?

andriy [413]

Answer:

M(x₄ ,y₄) = (-3.5 , 0.5) and

N (x₅ ,y₅) = ( -1 , -0.5 )

Step-by-step explanation:

Let the endpoint coordinates for the mid segment of △PQR that is parallel to PQ be

M(x₄ ,y₄) and N(x₅ ,y₅) such that MN || PQ

point P( x₁ , y₁) ≡ ( -3 ,3 )

point Q( x₂ , y₂) ≡ (2 , 1 )

point R( x₂ , y₂) ≡ (-4 , -2)

To Find:

M(x₄ ,y₄) = ? and

N (x₅ ,y₅) = ?

Solution:

We have Mid Point Formula as

$Mid\ point(x,y)=(\frac{x_{1}+x_{2} }{2}, \frac{y_{1}+y_{2} }{2})$

As M is the mid point of PR and N is the mid point of RQ so we will have

$Mid\ pointM(x_{4} ,y_{4})=(\frac{x_{1}+x_{3} }{2}, \frac{y_{1}+y_{3} }{2})$

$Mid\ pointN(x_{5} ,y_{5})=(\frac{x_{2}+x_{3} }{2}, \frac{y_{2}+y_{3} }{2})$

Substituting the given value in above equation we get

$Mid\ pointM(x_{4} ,y_{4})=(\frac{-3+-4 }{2}, \frac{3+-2} }{2})$

∴ $Mid\ pointM(x_{4} ,y_{4})=(\frac{-7} }{2}, \frac{1}{2})$

∴ $Mid\ pointM(x_{4} ,y_{4})=(-3.5, 0.5)$

Similarly,

$Mid\ pointN(x_{5} ,y_{5})=(\frac{2+-4 }{2}, \frac{1+-2 }{2})$

∴ $Mid\ pointN(x_{5} ,y_{5})=(\frac{-2 }{2}, \frac{-1}{2})$

∴ $Mid\ pointN(x_{5} ,y_{5})=(-1, -0.5)$

∴ M(x₄ ,y₄) = (-3.5 , 0.5) and

N (x₅ ,y₅) = ( -1 , -0.5 )

3 0

3 years ago

You plan to borrow $36,500 at a 7.7% annual interest rate. The terms require you to amortize the loan with 7 equal end-of-year p

erma4kov [3.2K]

The amount of interest you would be paying in Year 2 is: $2,492.62.

<h3>Interest</h3>

First step is to calculate the Equal Monthly Payment

Equal Monthly Payment=P×r×(1+r)^t/(1+r)^t-1

Where:

P=Principal=$36,500

r=Rate=7.7%

t=Time=7 years

Equal Monthly Payment=36,500×0.077×(1+0.077)^7÷(1+0.077)^7-1

Equal Monthly Payment=36,500×0.077×(1.077)^7÷(1.077)^7-1

Equal Monthly Payment=36,500×0.077×1.6807763÷1.6807763-1

Equal Monthly Payment=4,723.82/0.6807763

Equal Monthly Payment=$6,938.875

Second step is to calculate Year 1 Closing balance

Year 1 Closing balance = Beginning balance + Interest - EMI Payment

Year 1 Closing balance= $36,500 +($36,500×7.7%) - $6,938.875

Year 1 Closing balance= $36,500 + $2,810.5 -$6,938.875

Year 1 Closing balance = $32,371.625

Third step is to calculate year 2 interest

Year 2 Interest= $32,371.625×7.7%

Year 2 Interest=$2,492.62

Therefore the amount of interest you would be paying in Year 2 is: $2,492.62.

Learn more about interest here:brainly.com/question/15259578

#SPJ1

8 0

2 years ago

Need help for 18) 21) Solve each equation and check. Show all work please

Alexxandr [17]

18) (10)7d/10=35(10)
7d/7=350/7
d=50
21) 3/4 w=27
(4/3)3/4 w=27(4/3)
w=36
Hope this helps!

5 0

3 years ago

How do you do this question?

daser333 [38]

Answer:

B. 1/2

Step-by-step explanation:

$\lim_{z \to 0} \frac{g(z)e^{-z}-3}{z^{2}-2z}$

If we plug in 0 for z, we get 0/0. Apply l'Hopital's rule.

$\lim_{z \to 0} \frac{-g(z)e^{-z}+g'(z)e^{-z}}{2z-2}$

Now when we plug in 0 for z, we get:

$\frac{-g(0)e^{0}+g'(0)e^{0}}{2(0)-2}\\\frac{-g(0)+g'(0)}{-2}\\\frac{-3+2}{-2}\\\frac{1}{2}$

4 0

3 years ago

Find the distance between the points E(3, 7) and F(6, 5). The exact distance between the two points is .

S_A_V [24]

Answer:

$\sqrt{13}$

Step-by-step explanation:

The trick here is to know the distance formula (a formula that helps you find the distance between two points).

Distance formula: distance = $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

But now that we know this, we can simply plug in our values and solve!

$\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\sqrt{(6-3)^2+(5-7)^2}\\\sqrt{(3)^2+(-2)^2}\\\sqrt{9+4}\\\sqrt{13}$

Now we can tell from our answer that the distance between both points is $\sqrt{13}$

7 0

3 years ago