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bagirrra123 [75]

3 years ago

8

What are the possible numbers of positive, negative, and complex zeros of f(x) = −3x^4 + 5x^3 − x^2 + 8x + 4?

1 answer:

kvv77 [185]3 years ago

4 0

According to the fundamental theory of algebra, the number of solutions of an equation equals the degree of that equation.
This is a fourth degree equation, so there are 4 solutions.

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I’ll mark Brainliest

yan [13]

Hello!!!

The Graph's Answer is below

<u>Nicole's Pattern Ian's Pattern Coordinate's Plane </u>

1 0 ( 1,0)

5 1 (5,1)

17 3 (17,3)

53 7 (53,7)

161 15 (161,15)

In order to get these answers, you start with 1 one Nicole's equation, and mutliply by 3, which gets you three. You then add two, which gets you five, after this, you continue to add Nicole's answer by three, then add five.For Ian's answer,you start with 0,then you add 1/2, which gives you .5 After you have this .5 you multiply by 2,which gives you one whole, you continue to add a half and mutliply by 2 for each answer. Nicole's answer is X,which means it is used first in our parentheses ( ),while ian's is Y and is used second.

I HOPE THIS HELPS! Good luck on your assignment and let me know if you need help with anything else <3!

6 0

2 years ago

Find the IQR of the data set in the dot plot

Sholpan [36]

Answer:

5.5 - 1.5 = 4

Brainliest pls

7 0

3 years ago

Suzannes school are painting a rectangular mural outside the buillding that will be 15 feet by 45 feet the students are also goi

tatuchka [14]

Answer:

THE LENGTH OF THE STUDENTS PAINTING=15/3=5

THE BREADTH OF THE STUDENTS PAINTING=45/3=15

AREA OF THEIR PAINTING=15×5=75

4 0

3 years ago

Coach Evans recorded the height, in inches of each player on his team. The results are shown.

marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile $(Q_1)$

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile $(Q_3)$

Terms in arranged in ascending order:

$57,60,60,61,62,62,63,63,64$

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

$Q_1$ is median of terms $57,60,60,61$

Number of terms (n) = 4

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60$

So, $Q_1=60$

So, 25% of the heights of a team is less than 60 inches

$Q_3$ is the median of terms $62,63,63,64$

Median = $\frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th} }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63$

So, $Q_3=63$

So, 75% of the heights of a team is less than 63 inches

Interquartile range = $Q_3-Q_1=63-60=3$

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0

2 years ago

What’s the slope of the line on the graph?

Anuta_ua [19.1K]

The slope would be 2x

7 0

3 years ago